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Mashcka [7]
4 years ago
10

X+3<8 and 3(x+4)-11<10

Mathematics
1 answer:
kondaur [170]4 years ago
4 0

Answer:

<h3>X<5 and X<3</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.

x+3<8 and 3(x+4)-11<10

x+3<8

x+3-3<8-3 (First, subtract 3 from both sides.)

8-3 (Solve.)

8-3=5

x<5

3(x+4)-11<10

3(x+4)-11+11<10+11 (Add 11 from both sides.)

10+11 (Solve.)

10+11=21

3(x+4)<21

3(x+4)/3<21/3 (Next, divide by 3 from both sides.)

21/3 (Solve.)

21/3=7

x+4<7

x+4-4<7-4 (Then, subtract 4 from both sides.)

7-4=3

x<3

The correct answer is x<5 and x<3.

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Which equation represents the line that passes through points (1, -5) and (3,-17)
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Answer:

A) y=-6x+1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

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y-y1=m(x-x1)

y-(-5)=-6(x-1)

y+5=-6(x-1)

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Step-by-step explanation:

No, Lance's thinking is wrong because you cannot compare decimal numbers with alphabetizing words. For example, if we compare 37.6 to 7.42 using the method of Lance, we would probably say 37.6 is less than 7.42 because 3 is less than 7. But it is wrong. The 3 in 37.6 is in the tens place. On the other hand, 7.42 contains no tense. Therefore, 37.6 is actually higher.

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