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Mashcka [7]
3 years ago
10

X+3<8 and 3(x+4)-11<10

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

<h3>X<5 and X<3</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.

x+3<8 and 3(x+4)-11<10

x+3<8

x+3-3<8-3 (First, subtract 3 from both sides.)

8-3 (Solve.)

8-3=5

x<5

3(x+4)-11<10

3(x+4)-11+11<10+11 (Add 11 from both sides.)

10+11 (Solve.)

10+11=21

3(x+4)<21

3(x+4)/3<21/3 (Next, divide by 3 from both sides.)

21/3 (Solve.)

21/3=7

x+4<7

x+4-4<7-4 (Then, subtract 4 from both sides.)

7-4=3

x<3

The correct answer is x<5 and x<3.

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Step-by-step explanation:

<u>Given:</u> ΔABC,

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<u>Solution:</u>

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2. ∠CDB is a right ange, because CD⊥AB, so

m\angle CDB=90^{\circ}

3. Consider triangle ACD. The sum of the measures of all interior angles is always 180°, so

m\angle A+m\angle ADC+m\angle ACD=180^{\circ}\\ \\50^{\circ}+90^{\circ}+m\angle ACD=180^{\circ}\\ \\m\angle ACD=180^{\circ}-50^{\circ}-90^{\circ}=40^{\circ}

4. By Angle Addition Postulate,

m\angle ACD+m\angle BCD=m\angle ACB\\ \\40^{\circ}+m\angle BCD=85^{\circ}\\ \\m\angle BCD=85^{\circ}-40^{\circ}=45^{\circ}

5. Consider triangle ABC. The sum of the measures of all interior angles is always 180°, so

m\angle A+m\angle ACB+m\angle B=180^{\circ}\\ \\50^{\circ}+85^{\circ}+m\angle B=180^{\circ}\\ \\m\angle B=180^{\circ}-50^{\circ}-85^{\circ}=45^{\circ}

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tigry1 [53]

Answer:

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Step-by-step explanation:

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Answer:

<h3>p(+)q=SQR(p^2+q^2)</h3>

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Step-by-step explanation:

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David's money is three times Siti's money. Farid has RM 150 less than Siti. The total amount of their money is RM 2 000. How muc
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Answer:

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Step-by-step explanation:

Let

Siti's money = x

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