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Mashcka [7]
3 years ago
10

X+3<8 and 3(x+4)-11<10

Mathematics
1 answer:
kondaur [170]3 years ago
4 0

Answer:

<h3>X<5 and X<3</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.

x+3<8 and 3(x+4)-11<10

x+3<8

x+3-3<8-3 (First, subtract 3 from both sides.)

8-3 (Solve.)

8-3=5

x<5

3(x+4)-11<10

3(x+4)-11+11<10+11 (Add 11 from both sides.)

10+11 (Solve.)

10+11=21

3(x+4)<21

3(x+4)/3<21/3 (Next, divide by 3 from both sides.)

21/3 (Solve.)

21/3=7

x+4<7

x+4-4<7-4 (Then, subtract 4 from both sides.)

7-4=3

x<3

The correct answer is x<5 and x<3.

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