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Mashcka [7]
4 years ago
10

X+3<8 and 3(x+4)-11<10

Mathematics
1 answer:
kondaur [170]4 years ago
4 0

Answer:

<h3>X<5 and X<3</h3>

Step-by-step explanation:

To solve this problem, first, you have to isolate it on one side of the equation. Remember to solve this problem, isolate x on one side of the equation.

x+3<8 and 3(x+4)-11<10

x+3<8

x+3-3<8-3 (First, subtract 3 from both sides.)

8-3 (Solve.)

8-3=5

x<5

3(x+4)-11<10

3(x+4)-11+11<10+11 (Add 11 from both sides.)

10+11 (Solve.)

10+11=21

3(x+4)<21

3(x+4)/3<21/3 (Next, divide by 3 from both sides.)

21/3 (Solve.)

21/3=7

x+4<7

x+4-4<7-4 (Then, subtract 4 from both sides.)

7-4=3

x<3

The correct answer is x<5 and x<3.

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How many times can 0.1 fit into 100?
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Answer:

1000 times

Step-by-step explanation:

To find out how many times 0.1 can fit into 100, we can just divide 100 by 0.1.

But, we first find out how many times can 1 fit into 100.

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How to show you can use Distributive Property to rewrite and find (32×4)+(32×4).
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Answer:

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Step-by-step explanation:

6 0
3 years ago
What were the two whole numbers of 5x(8 3)?
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3 years ago
The first two terms of a sequence are a1 =4 and a2= -2. Let a3 be the third term when the sequence is arithmetic and let b3 be t
stepan [7]

Answer:

a3 + b3 = -7

Step-by-step explanation:

When the sequence is A.P

a1 =4 and a2= -2

Common difference,d = a2 - a1

= -2 - 4

d = -6

a3 = third term

a3 = a1 + 2d

= 4 + 2(-6)

= 4 - 12

= -8

a3 = -8

When the sequence is geometric

a1 =4 and a2= -2

Common ratio, r = a2/a1

= -2/4

r = -1/2

Or

r = -0.5

b3 = third term

b3 = ar²

= 4 * (-1/2)²

= 4 * 1/4

= 4/4

= 1

b3 = 1

a3 + b3 = -8 + 1

= -7

a3 + b3 = -7

8 0
3 years ago
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