At two points close together toward the upper right of the diagram, since X and Y chromosomes are more advanced.
Answer:
<h2>
Haploid=13</h2><h2>
triploid=39 </h2><h2>
tetraploid=52</h2><h2>
trisomic=14 </h2><h2>
monosomic=12</h2>
Explanation:
Given;
A species with a diploid number of 26, so 26= 2n ( a diploid cell),
so in haploid condition, chromosome number becomes half (13 in this case). triplod is when 2n + n, and 2n +2n ( tetploid). Trisomy and monosomy is the addition or deletion of a sinlge chromosome of a sinlge set .
Haploid=13, one chromosome from each pair of chromosome set,
triploid=39 (13× 3); diploid+ n( 3n)
tetraploid=52 (13× 4) 4n
trisomic=14 (13+1) ; n+1
monosomic=12 (13-1); n-1
The complete question is:
If these organisms were arraigned in a food pyramid, which organism would have the least amount of total energy available?
- Producers
- Carnivore
- Herbivores
- Top predators
Answer: Top predators
Explanation:
The top predators get the least energy because according to the 10 per cent law the energy transfer only 10 energy is transferred to the next successive level.
The next level of the organism receives only 10 of the total energy that the previous level has.
Hence, the top predators have the least amount of energy in it as the energy is transferred through various levels before reaching top predators.
