Question

I really hope someone can hekp me with my hwit's linear equations...

Answer 1

You first should isolate the "y" in the equation.

3x - 2y = 6 Subtract 3x on both sides

3x - 3x - 2y = 6 - 3x

-2y = 6 - 3x  Divide -2 on both sides to get "y" by itself

$y = \frac{6-3x}{-2}$

$y = -3 + \frac{3}{2} x$

This equation is:

y = mx + b

"m" being the slope, "b" being the y-intercept (when x = 0)

The y-intercept is -3 in the equation. So you can eliminate choices A and C.

You can plug in any of the numbers of x(-2 , -1 , 0, 1, 2) into this equation, to find it's y value.

You can plug in 1 for x:

y = -3 + $\frac{3}{2} x$

y = -3 + $\frac{3}{2} (1)$

y = -3 + $\frac{3}{2}$  Make the denominators the same

$y = \frac{-6}{2} +\frac{3}{2} = \frac{-3}{2}$

Your answer is B