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3 years ago

I really hope someone can hekp me with my hwit's linear equations...

Mathematics

1 answer:

olchik [2.2K]3 years ago

6 0

You first should isolate the "y" in the equation.

3x - 2y = 6 Subtract 3x on both sides

3x - 3x - 2y = 6 - 3x

-2y = 6 - 3x Divide -2 on both sides to get "y" by itself

$y = \frac{6-3x}{-2}$

$y = -3 + \frac{3}{2} x$

This equation is:

y = mx + b

"m" being the slope, "b" being the y-intercept (when x = 0)

The y-intercept is -3 in the equation. So you can eliminate choices A and C.

You can plug in any of the numbers of x(-2 , -1 , 0, 1, 2) into this equation, to find it's y value.

You can plug in 1 for x:

y = -3 + $\frac{3}{2} x$

y = -3 + $\frac{3}{2} (1)$

y = -3 + $\frac{3}{2}$ Make the denominators the same

$y = \frac{-6}{2} +\frac{3}{2} = \frac{-3}{2}$

Your answer is B

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Answer:

The test statistic Z = 3.125

Step-by-step explanation:

Given Population proportion P = 0.25

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Sample proportion 'p⁻' = 0.30

Test statistic

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Final answer:-

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Let X1 and X2 be two random variables following Binomial distribution Bin(n1,p) and Bin(n2,p), respectively. Assume that X1 and

ryzh [129]

Answer:

a) X1+X2 have distribution Bi(n1+n2, p)

P(X1+X2 = 1 | X2 = 0) = np(1-p)ⁿ¹⁻¹

P(X1+X2 = 1| X2 = 1) = (1-p)ⁿ¹

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Step-by-step explanation:

Since both variables are independent but they have the same probability parameter, you can interpret that like if the experiment that models each try in both variables is the same. When you sum both random variables toguether, what you obtain as a result is the total amount of success in n1+n2 tries of the same experiment, thus X1+X2 have distribution Bi(n1+n2, p).

Note that, if X2 = k, then X1+X2 = 1 is equivalent to X1 = 1-k. Since X1 and X2 are independent, then P(X1+X2 = 1| X2 = K) = P(X1=1-k|X2=k) = P(X1 = 1-k).

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If k = 1, then it is equal to P(X1 = 0) = (1-p)ⁿ¹

Thus,

P(X1+X2 = 1) = P(X1+X2 = 1| X2 = 1) * P(X2=1) + P(X1+X2 = 1| X2 = 0) * P(X2 = 0) = (1-p)ⁿ¹ * np(1-p)ⁿ²⁻¹+ (1-p)ⁿ²*np(1-p)ⁿ¹-¹

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3 years ago

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Step-by-step explanation:

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