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2 years ago

I really hope someone can hekp me with my hwit's linear equations...

Mathematics

1 answer:

olchik [2.2K]2 years ago

6 0

You first should isolate the "y" in the equation.

3x - 2y = 6 Subtract 3x on both sides

3x - 3x - 2y = 6 - 3x

-2y = 6 - 3x Divide -2 on both sides to get "y" by itself

$y = \frac{6-3x}{-2}$

$y = -3 + \frac{3}{2} x$

This equation is:

y = mx + b

"m" being the slope, "b" being the y-intercept (when x = 0)

The y-intercept is -3 in the equation. So you can eliminate choices A and C.

You can plug in any of the numbers of x(-2 , -1 , 0, 1, 2) into this equation, to find it's y value.

You can plug in 1 for x:

y = -3 + $\frac{3}{2} x$

y = -3 + $\frac{3}{2} (1)$

y = -3 + $\frac{3}{2}$ Make the denominators the same

$y = \frac{-6}{2} +\frac{3}{2} = \frac{-3}{2}$

Your answer is B

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If m<6=123.5 degrees, Then m<1 is A.)56.5 B.)67.5 C.)123.5 D.)136.5

DerKrebs [107]

The answer to this question is A - 56.5.
Angles 6 and 1 are both on a 180 degree line. When we subtract the measurement of 6 from 180 degrees, we can get the measurement for angle 1.

7 0

2 years ago

Read 2 more answers

Help me please this was due yesturday

stepan [7]

Step-by-step explanation:

Slope intercept form is

$y = mx + b$

where m is the slope( average rate of change) and b is the

y intercept( the y value when x is zero).

When x=0, y is 2. This means b=2

Slope is change in y value/ change in x value. Another obvious arbitrary point we are given is (-8,0).

So let use the formula we given.

So our slope is 1/4 so our equation is

1/4x+2

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2 years ago

Will the following two equations have a solution? Explain. y = 3x + 5 y = 3x - 7

r-ruslan [8.4K]

Answer:

There is no solution because the slopes of the two lines are the same.

Step-by-step explanation:

3x + 5 = 3x - 7

-3x - 3x Subtract 3x from both sides

5 ≠ - 7 No solution

If this answer is correct, please make me Brainliest!

7 0

3 years ago

Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - α)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of t for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$