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Otrada [13]
2 years ago
5

Help! what is 302938*4043

Mathematics
2 answers:
bonufazy [111]2 years ago
6 0

Answer:

1,224,778,334

Step-by-step explanation:

302938 \times 4043

= 1224778334

Hope it helps you!!

#IndianMurga(. ❛ ᴗ ❛.)

jenyasd209 [6]2 years ago
4 0

Answer:

302938 x 4043 = 1.22477833e9

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Could someone please answer these two
exis [7]

Answer:

SEE BELOW

Step-by-step explanation:

1. find value of m

a^2 + b^2 = c^2

7.5^2+10^2=c^2

15+100=c^2

115=c^2

square it

=10.7 (not answer)

a^2+b^2=c^2

10.7^2+30^2=c^2

114.49+900=c^2

1014.49=c^2

square it

m=31.9

2.20^2 + 21^2 = 841

29^2=841

yes the triangle is right angled !!!

hope this helps :)

6 0
3 years ago
Solve 13 and 14, please.
Amiraneli [1.4K]

Answer: The answer to 13 is 30. but one row will only have 1

Step-by-step explanation:If you divide 121 by 4 you will get a answer of 30 with a remainder of 1. since it is a uneven number. So you will have one row with only 1 chair.

3 0
3 years ago
As a sales person, Harvey earns $60 per day plus 1⁄4 of his customer sales. If Harvey
zimovet [89]

Answer

$60+1/4c=$147.50

Step-by-step explanation:

makes $60 a day

1/4 of customer sales= 1/4 c

equal 147.50

so 60+ 1/4 c = 147.50

7 0
3 years ago
Neilsen Cookie Company sells its assorted butter cookies in containers that have a net content of 1 lb. The estimated demand for
vesna_86 [32]

Answer:

  37,528 containers of cookies

Step-by-step explanation:

a) <u>Cost Function</u>

For the fixed annual demand of 500,000 containers, the manufacturing cost of $0.53 each will total ...

  manufacturing cost = 500,000×$0.53 = $265,000 annually.

For a production batch size of x containers, those x containers will be put into storage, and withdrawn at the uniform rate of 500,000 containers per year. On average, (1/2)x containers will be in storage, so storage costs will be ...

  storage cost = (1/2)($0.36x) = $0.18x . . . . annually

For annual demand of 500,000 containers, and a production batch size of x, there will be 500,000/x production batches each year. The setup cost is $507 for each of those, so the annual setup cost is ...

  setup cost = (500,000/x)($507) = $253,500,000/x . . . . annually

The total cost of producing 500,000 containers annually will be ...

  C = setup cost + storage cost + manufacturing cost

  C(x) = 253,500,000/x + 0.18x + 265,000

__

b) <u>Minimal-Cost Batch Size</u>

Cost will be minimized when its derivative with respect to x is zero.

  dC/dx = -253,500,000/x^2 +0.18 = 0

  x^2 = 253,500,000/0.18 . . . . . . . solve for x^2

  x ≈ 37,527.8 ≈ 37,528 . . . . . . . . . take the square root

The size of the production run that will minimize production cost is 37,528 boxes.

_____

<em>Comment on the solution</em>

You may notice that the equation we finally solve for batch size is equivalent to one that sets setup cost equal to storage cost:

  253,500,000/x = 0.18x

This relation (setup cost = storage cost) is the general solution for this sort of problem regarding batch size.

8 0
3 years ago
4. What is the circumference of a circle with a radius of 4 cm?
zepelin [54]

Answer:

25.13

Step-by-step explanation:

2 π r

2 x π x 4 =25.13

8 0
3 years ago
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