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4 years ago

What numbers is the multiple of 6

2 answers:

5 0

The first 20 multiples of 6 are :

6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78, 84, 90, 96, 102, 108, 114, 120.

LuckyWell [14K]4 years ago

4 0

6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96,102,108,114,120,126,132,138,144,150,156,162,168,174,180,186,192,198,204,210,216,222,228,234,240,246,252,258,264,270,276,282,288,294.

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Two HS math questions with good points attached. Show / Explain Steps

Alika [10]

V = C(1 - (T/N)).......for C ....multiply both sides by N
NV = CN - CT
NV = C(N - T) ...divide both sides by (N-T)
NV / (N - T) = C

V = C(1 - (T/N))...for T ...multiply both sides by N
NV = CN - CT ....subtract CN from both sides
NV - CN = - CT....divide both sides by -C
(NV - CN) / -C = T or (CN - NV)/ C = T

4 0

3 years ago

The cost of producing x bags of dog food is given by C(x) = 800 + 400 + 10x - x where 0 SX 55000. Find the marginal-cost functio

nikdorinn [45]

Answer:

The marginal-cost function is;

c'(x)= (20x-1)/(2√(400 + 10x² - x))

Completed question;

The cost of producing x bags of dog food is given by C(x) = 800 + √(400 + 10x² - x) where 0≤x≤55000. Find the marginal-cost function.

The marginal-cost function is c'(x)=

(Use integers or fractions for any numbers in the expression.)

Step-by-step explanation:

The marginal-cost function is c'(x)= = dC(x)/dx

Where;

C(x) = 800 + √(400 + 10x² - x)

c'(x) = d(800 + √(400 + 10x² - x) )/dx

Using function of function rule of differentiation or chain rule;

c'(x) = (20x-1)×(1/2√(400 + 10x² - x))

c'(x) = (20x-1)/(2√(400 + 10x² - x))

The marginal-cost function is;

c'(x)= (20x-1)/(2√(400 + 10x² - x))

3 0

4 years ago

What number should be added to both sides of the equation to complete the square?

lubasha [3.4K]

Answer:

9 should be added to both sides of the equation to complete the square.

Step-by-step explanation:

Given : $x^2 -6x = 5$

To Find: What number should be added to both sides of the equation to complete the square?

Solution:

$x^2 -6x = 5$

Add the square of half of coefficient of x

So, the square of half of coefficient of x = $(\frac{6}{2})^2=3^2 =9$

So, $x^2 -6x +9 = 5+9$

$x^2 -6x +3^2 = 5+9$

$x^2 -2 \times 3 \times x +3^2 = 5+9$

$(x-3)^2 = 5+9$

$(x-3)^2 =14$

Thus 9 should be added to both sides of the equation to complete the square.

8 0

3 years ago

It took Alan six hours to make nine paintings he spent an equal amount of time making each painting how many minutes did he spen

Gennadij [26K]

Let's say he took half an hour to make half a painting he required a quarter of an hour.

3 0

3 years ago

Read 2 more answers

Which of the following are lengths of the sides of a 30°-60°-90° triangle? A. 5√3, 15., 10√3 units B. 3, 4, and 5 units C. √3, 3

zaharov [31]

Answer:

Step-by-step explanation:

law of sine

c/sin(C) = b/sin(B) = a/sin(A)

with the sides and corresponding angles being always opposite.

sin(90) = 1

sin(30) = 0.5

c, the Hypotenuse, is the longest side in such a right-angled triangle.

c/1 = b/0.5

b = c×0.5 = c/2

so, one side has to be half the length of the longest side (Hypotenuse).

the only answer meeting that criteria is A.

the longest side is 10×sqrt(3) = 17.32...

the side half of that is 5×sqrt(3).

and Pythagoras for such a triangle is then

c² = (c/2)² + a²

c² = c²/4 + a²

so, a² = 3c²/4

c² = c²/4 + 3c²/4

therefore we can check also the third side

15² = 3×(5×sqrt(3))² = 3×25×3 = 3×75 = 225 = 15²

correct.

A is such a triangle.

5 0

2 years ago