Question

All of the following points lie on the graph of y = 3 x except _____. (0, 1) (1, 3) (2, 6) (3, 27)

Answer 1

Answer:

The answer is (0,1) and (3,27)

Step-by-step explanation:

Given points (0,1)(1,3)(2,6)(3,27)

and equation of line y=3x .........[1]

The points that will satisfy the equation lie on it

Taking (0,1) : Putting it in [1]  It does not satisfy it as 3*0=0

Taking (1,3): When we put it in [1] 1*3=3

i.e. it satisfy the equation

Taking (2,6): When we put it in [1] 2*3=6

i,e, it satisfy the equation

Taking (3,27): On putting it in [1] 3*3= 9

i.e. it does not satisfy the equation

Hence (0,1) (3,27) does not lie on y=3x

Answer 2

Answer:

Point (0,1) and  (3,27) does not lies on the graph y = 3x

Step-by-step explanation:

Consider the given graph of y = 3x

We  have to check out of given points (0, 1) (1, 3) (2, 6) (3, 27) lies on the graph y= 3x.

We put x values in equation of given graph y = 3x and see if we get the y values.

1) (0, 1)

Graph equation x = 0 then 3(0)= 0 ≠ 1

Thus, point (0, 1) does not lies on the graph y = 3x

2) (1, 3)

Graph equation x = 1 then 3(1) = 3 = y

Thus, point (1, 3) lies on the graph y = 3x.

3) (2, 6)

Graph equation x = 2 then 3(2)= 6 = y

Thus, point (2, 6) lies on the graph y = 3x.

4) (3, 27)

Graph equation x = 3 then 3(3)= 9 ≠ 27

Thus, point (3,27) does not lies on the graph y = 3x

We can also check by seeing the graph of y = 3x (attached below)

Thus, Point (0,1) and  (3,27) does not lies on the graph y = 3x