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sergij07 [2.7K]

3 years ago

6

Can someone explain how to do this worksheet? when graphing the lines they don't seem to intersect with a UFO.

1 answer:

GREYUIT [131]3 years ago

5 0

Answer:

There are 2 equations together in each box, so what you need to do is graph them both. Then see where they intersect, that will be where the ufo they shot is. For example On the first two set of equations (y=x+6 & y=-x-4) when graphed together they intersect at (-5,1) which is where ufo 6 is. Meaning they shot Ufo 6

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Given two circles, X and Y, with radii 2in and 9in respectively, the ratio of the areas is (Write you answer as a fraction)

iris [78.8K]

A= pi (r)^2
Area of circle x. A = pi 2^2 or 4 pi
Area of circle y A= pi (9)^2 or 81 pi
Answer= 4/81

6 0

3 years ago

Read 2 more answers

Directions: Compare the sides and angles by filling in the blank with a < or > symbol.

Katyanochek1 [597]

The correct comparison as shown in the figures are:

QR < QS
AB > CD
m<FJG > m<HJG
m<QSP > m<QSR

From the given diagram, we are to fill in the blank spaces with a < or > symbol.

21) The measure of the angles is a function of the measure of the sides.

Since the angle facing the side QR is less than that of QS, hence QR < QS

22) Similarly for this figure, the angle facing the side AB is greater than that of CD, hence AB > CD

23) Also, for this figure, the side facing the angle m<FJG is greater than the side facing the angle m<HJG, hence m<FJG > m<HJG

24) Also, for this figure, the side facing the angle m<QSP is greater than the side facing the angle m<QSR, hence m<QSP > m<QSR

Learn more on angles here: brainly.com/question/16281260

8 0

2 years ago

Whats (2^–1)^3 with the same base but one exponent??

STatiana [176]

Step-by-step explanation:

$({2}^{ - 1} )^{3}$

${2}^{ - 3}$

........

5 0

4 years ago

How can she might choose a random sample of five students from her class of 35 students?

shtirl [24]

Answer:

who?

Step-by-step explanation:

7 0

3 years ago

Find the area of each regular polygon. Round your answer to the nearest tenth if necessary

Gnesinka [82]

Answer:

Step-by-step explanation:

13). Area of a square = (Side)²

= (BC)²

Since, diagonals of a square bisect each other at 90°,

ΔBOC is a right triangle.

By applying Pythagoras theorem in the given triangle,

BC² = OB² + OC²

BC² = 2(OB)²

BC² = 2(7√2)²

BC = $\sqrt{196}$

Area of square ABCD = (BC)²

= (√196)²

= 196 units²

14). Measure of interior angles of the regular hexagon = 120°

Area of the regular hexagon = $\frac{3\sqrt{3}}{2}(\text{side})^2$

From the given picture,

m∠BAC = m∠ABC = m∠ACB = 60°

Therefore, ΔABC is an isosceles triangle.

And all sides of this triangle will be equal in measure.

AB = AC = BC = 9 units

Area of the given regular hexagon = $\frac{3\sqrt{3}}{2}(9)^2$

= 210.44 square units

≈ 210.4 square units

5 0

3 years ago