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Ivenika [448]
3 years ago
12

Mary covered her kitchen floor with 10 tiles. The floor measures 6 feet long by 5 feet wide, The tiles are each 3 feet long and

w feet wide. Write an equation to represent the situation.
Mathematics
1 answer:
Tcecarenko [31]3 years ago
7 0
Number of tiles used for covering the kitchen floor = 10
Area covered by the floor = 6 * 5 feet^2 <span><span>                                              
                                         = 30 square feet</span>
</span> Length of each tiles = 3 feet
Width of each tiles = w feet
Area covered by each tiles = 3w square feet
Then the equation can be written as
3w * 10 = 30
30w = 30
 w= 30/30 <span>    
    = 1 feet</span>
So the width of each tiles is 1 feet. I hope the procedure is clear enough for you to understand. The equation to determine the solution is
10 *3w = 30
There are 10 tiles used and the area covered by each tiles is 3w. Also the area of the floor is 30 square feet. All those information's have been used to get to the equation.



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Alborosie

Answer:

x = 5

Step-by-step explanation:

The given equation is :

2(1+7x)=72

Use the distributive property to the LHS.

2(1)+2(7x) = 72

2+14x = 72

Subtract 2 from both sides.

2+14x-2 = 72-2

14x = 70

x = 70/14

x = 5

So, the answer of the given equation is x = 5.

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Toxaphene is an insecticide that has been identified as a pollutant in the Great Lakes ecosystem. To investigate the effect of t
Likurg_2 [28]

Answer:

This data suggest that there is more variability in low-dose weight gains than in control weight gains.

Step-by-step explanation:

Let \sigma_{1}^{2} be the variance for the population of weight gains for rats given a low dose, and \sigma_{2}^{2} the variance for the population of weight gains for control rats whose diet did not include the insecticide.

We want to test H_{0}: \sigma_{1}^{2} = \sigma_{2}^{2} vs H_{1}: \sigma_{1}^{2} > \sigma_{2}^{2}. We have that the sample standard deviation for n_{2} = 22 female control rats was s_{2} = 28 g and for n_{1} = 18 female low-dose rats was s_{1} = 51 g. So, we have observed the value

F = \frac{s_{1}^{2}}{s_{2}^{2}} = \frac{(51)^{2}}{(28)^{2}} = 3.3176 which comes from a F distribution with n_{1} - 1 = 18 - 1 = 17 degrees of freedom (numerator) and n_{2} - 1 = 22 - 1 = 21 degrees of freedom (denominator).

As we want carry out a test of hypothesis at the significance level of 0.05, we should find the 95th quantile of the F distribution with 17 and 21 degrees of freedom, this value is 2.1389. The rejection region is given by {F > 2.1389}, because the observed value is 3.3176 > 2.1389, we reject the null hypothesis. So, this data suggest that there is more variability in low-dose weight gains than in control weight gains.

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klasskru [66]

Answer:

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3 years ago
What is the cube root of 27x18? 3x6 3x9 9x6 9x9
vredina [299]

Solution:

A is the correct option.

Explanation:

We have to find the cube root of 27x^{18}

In order to find the cube root of the expression, we find the factors of 27.

27= 3 \times 3\times 3= 3^3

Also x^18 can be written as

x^{18}=(x^6)^3

Replace the given expression with these values, we get

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Now, we have the formula,

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Using this formula, the cube with the cube root got cancelled and we are left with

\sqrt[3]{27x^{18}} = 3\cdot x^6

Therefore, the cube root of 27x^18 is 3x^6.

A is the correct option.

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