Question

I shall give the right answer brainliest

Answer 1

Answer:

A. $-\frac{1}{9}$

Step-by-step explanation:

-($3^-^5$)($3^3$) = $-\frac{1}{9}$

please let me know if I am wrong.

hope this helped.

Answer 2

Answer:

A

Step-by-step explanation:

$-\left(3^{-5}\right)\left(3^3\right)$

$\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}$

$3^{-5}\cdot \:3^3=3^{-5+3}$

= $-3^{-5}\cdot \:3^3$

$\mathrm{Add/Subtract\:the\:numbers:}\:-5+3=-2$

$=-3^{-2}$

= $\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}$

$3^{-2}=\frac{1}{3^2}$

= $=-\frac{1}{3^2}$

$3^2=9$

= $=-\frac{1}{9}$