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Norma-Jean [14]
2 years ago
14

I shall give the right answer brainliest

Mathematics
2 answers:
Rina8888 [55]2 years ago
6 0

Answer:

A. -\frac{1}{9}

Step-by-step explanation:

-(3^-^5)(3^3) = -\frac{1}{9}

please let me know if I am wrong.

hope this helped.

zheka24 [161]2 years ago
3 0

Answer:

A

Step-by-step explanation:

-\left(3^{-5}\right)\left(3^3\right)

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}

3^{-5}\cdot \:3^3=3^{-5+3}

= -3^{-5}\cdot \:3^3

\mathrm{Add/Subtract\:the\:numbers:}\:-5+3=-2

=-3^{-2}

= \mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}

3^{-2}=\frac{1}{3^2}

= =-\frac{1}{3^2}

3^2=9

= =-\frac{1}{9}

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Answer:

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Step-by-step explanation:

Given that:

1. P(x) = \frac{2}{3x - 1}

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Thus,

P(x) ÷ Q(x) = \frac{2}{3x - 1} ÷ \frac{6}{-3x + 2}

Flip the 2nd function, Q(x), upside down to change the process to multiplication.

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Make both expressions as a single fraction by finding, the common denominator, divide the common denominator by each denominator, and then multiply by the numerator. You'd have the following below:

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3. P(x) - Q(x) = \frac{2}{3x - 1} - \frac{6}{-3x + 2}

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P(x)*Q(x) = \frac{2*6}{(3x - 1)(-3x + 2)}

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