
<em><u>Solution:</u></em>
<em><u>Given that,</u></em>

We have to write in simplest form
<em><u>Use the following law of exponent</u></em>

Using this, simplify the given expression

Thus the given expression is simplified
Linear function: d = -4m+50 (that's a negative 4 btw)
Slope: -4
y-intercept: 50
I'm truly sorry but I forgot how to do the last one :(
Answer:
third option (-3,3,5,9)
Step-by-step explanation:
domain is the starting point of the set (x coordinate )
Answer:
27
Step-by-step explanation:
Let <em>g </em>be Gabrielle's age and <em>m </em>be Mikhail's age.
We can turn the statements the problem gives us into mathematical expressions to help us solve.
Gabrielle's age is two times Mikhail's age:
<em>g </em>= 2<em>m</em>
The sum of their ages is 81:
<em>g </em>+ <em>m </em>= 81
This gives us a system of equations that will allow us to solve for Gabrielle's age.
<em>g </em>+ <em>m </em>= 81
(2<em>m</em>)<em> </em>+ <em>m </em>= 81
3<em>m </em>= 81
<em>m</em> = 
<em>m </em>= 27
If we need to solve for Gabrielle's age, we can do the following.
<em>g </em>= 2<em>m</em>
2(27)<em> </em>= <em>g</em>
54 = <em>g</em>
g = 54
Mikhail's age is 27.
Gabrielle's age is 54.
Answer:
x = 36.3°
using tane rule:

Here!
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


( rounded to nearest tenth of a degree)