SO, first you divide the numerator by the denominator.
Then write it like this:
Then write it like this:
Mr.giarmo left his home to travel to work at 7:15a.m. 25 minutes later he arrived at work whay time did Mr hiarmo arrive at work
1 answer:
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The altitudes of equal length, BE and CF gives AB = AC, from which we have;
- ∆ABC is an isosceles triangle
From the given description, we have;
BE = CF
<CFB = <BEC = 90° All right angles are congruent
BC = BC by reflexive property of congruency
BC = The hypotenuse side of triangles ∆BFC and ∆CEB
Therefore;
∆BFC is congruent to ∆CEB by Right angle Hypotenuse Side, RHS, rule of congruency.
Therefore;
BF = CE by Corresponding Parts of Congruent Triangles are Congruent, CPCTC
Similarly, we have;
∆AEB is congruent to ∆AFC, by Side-Angle-Angle, SAA, rule of congruency
Which gives;
FA = AE by CPCTC
BF + FA = CE + AE, by substitution property of equality
BF + FA = AB
CE + AE = AC
Therefore;
- AB = AC
Therefore;
- ∆ABC is an isosceles triangle
Learn more about rules of congruency here:
#SPJ1
Answer: Angle C = 51.5°
Step-by-step explanation:
The diagram of the triangle is shown in the attached photo.
we would apply the law of Cosines which is expressed as
c² = a² + b² - 2bcCosC
Where a,b and c are the length of each side of the triangle and C is the angle corresponding to c.
Therefore,
18² = 23² + 14² - 2(23 × 14)CosC
324 = 529 + 196 - 2(322)CosC
324 = 725 - 644CosC
644CosC = 725 - 324
644CosC = 401
CosC = 401/644
CosC = 0.623
C = Cos^- 1(0.623)
C = 51.5° to the nearest tenth
