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zmey [24]
3 years ago
6

In triangle ABC, the lengths of the sides in feet are a=23, b=14, c=18 . Find angle C.

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
7 0

Answer: Angle C = 51.5°

Step-by-step explanation:

The diagram of the triangle is shown in the attached photo.

we would apply the law of Cosines which is expressed as

c² = a² + b² - 2bcCosC

Where a,b and c are the length of each side of the triangle and C is the angle corresponding to c.

Therefore,

18² = 23² + 14² - 2(23 × 14)CosC

324 = 529 + 196 - 2(322)CosC

324 = 725 - 644CosC

644CosC = 725 - 324

644CosC = 401

CosC = 401/644

CosC = 0.623

C = Cos^- 1(0.623)

C = 51.5° to the nearest tenth

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