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xz_007 [3.2K]
3 years ago
10

the general rule of thumb is that the _____a substance's atoms and the _____ the bonds, the harder the substance

Mathematics
2 answers:
RSB [31]3 years ago
7 0

Answer:

Smaller and stronger.

Step-by-step explanation:

The general rule of thumb is that the SMALLER a substance's atoms and the STRONGER the bonds, the harder the substance.

Two of the strongest forms of chemical bond are the ionic and the covalent bonds.

aleksklad [387]3 years ago
5 0
<span>The general rule of thumb is that the smaller a substance's atoms and the stronger the bonds, the harder the substance to react and interact with other atoms. Since the stability is higher. Hope this answers the question. Have a nice day.</span>
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3 years ago
Chosse the replacement for x that makes the equation a true statement.
natita [175]

Answer:

x=-8

Step-by-step explanation:

16x+35 = -93

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8 0
3 years ago
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. Shanice is making a garden. The area of the garden is 24 ft2. Use the following shape and information to find the base (6−4) a
crimeas [40]

Answer:

The base and height  of the garden are 4.60 ft and 5.60 ft.

Step-by-step explanation:

The area of the garden is, <em>A</em> = 24 ft².

The base height of the garden are:

base (<em>b</em>) = 6x - 4

height (<em>h</em>) = x + 3

Compute the value of <em>x</em> as follows:

A=\frac{1}{2}\times b \times h\\\\24=\frac{1}{2}\times (6x-4) \times (x+3)\\\\48=6x^{2}+18x-4x-12\\\\6x^{2}+14x-60=0\\\\3x^{2}+7x-30=0\\

The last equation is a quadratic equation.

Compute the roots of the quadratic equation as follows:

x = \frac{ -b \pm \sqrt{b^2 - 4ac}}{ 2a }\\x = \frac{ -14 \pm \sqrt{14^2 - 4(3)(-30)}}{ 2(3) }\\x = \frac{ -14 \pm \sqrt{556}}{ 6 }\\x = \frac{ -14 }{ 6 } \pm \frac{2\sqrt{139}\, }{ 6 }\\x = -\frac{ 7}{  3 } \pm \frac{ \sqrt{139}\, }{  3 }\\x = 1.59661\\x\approx 1.60

The value of base and height are:

\text{base}=6x-4=(6\times 1.60)-4=5.60\ \text{ft}\\\\\text{height}=x+3=1.60+3=4.60\ \text{ft}

Thus, the base and height  of the garden are 4.60 ft and 5.60 ft.

3 0
3 years ago
What is the derivative of te^-t/2
salantis [7]
Y = t*e^(-t/2)

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5 0
3 years ago
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PLEASE HELP ME!!!!!
Allushta [10]

Answer: (1,7) (2,9) (3,11) (4,13)

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y = 2(4) + 5

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3 0
4 years ago
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