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faust18 [17]
3 years ago
12

4) A garden is in the shape of a square with a perimeter of

Mathematics
1 answer:
Leni [432]3 years ago
7 0

Answer:

It costs $154.88 to build the fences.

Step-by-step explanation:

Perimeter of square = 4 \times Side

We are given that A garden is in the shape of a square with a perimeter of  56 feet.

So,4 \times side = 56

Side =\frac{56}{4}=14 feet

So, Side of square park = 14 feet

One fence is around the perimeter of the garden, whereas the second fence is 2 feet from the first fence on the outside.

Outer length = 14+2+2=18 feet

So, Perimeter of outer fence = 4 \times side = 4 \times 18 = 72 feet

Cost of fencing 1 foot = $1.21

Cost of fencing 56 feet =56 \times 1.21=67.76

Cost of fencing 72 feet = 72 \times 1.21=87.12

Total cost = 67.76+87.12=154.88

Hence It costs $154.88 to build the fences.

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bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

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Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

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Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

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3 years ago
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Hi, can someone help with these two questions ASAP! (Ignore the multiple choice I circled, not sure if it’s correct)
Sindrei [870]

Answer:

1) D. y = -\frac{3}{2}\cdot x^{12} -7\cdot x^{5}+\frac{2}{3}\cdot x -10

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1) A polynomial is an algebraic expression of the form p(x) = \Sigma \limits_{i = 0}^{n} c_{i}\cdot x^{i}, where n is the grade of the polynomial. In this case, the only equation that satisfies this definition is:

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<em>We</em><em> </em><em>can</em><em> </em><em>check</em><em> </em><em>that</em><em> </em><em>these</em><em> </em><em>are</em><em> </em><em>correct</em><em> </em><em>by</em><em> </em><em>plugging</em><em> </em><em>them</em><em> </em><em>in</em><em> </em><em>for</em><em> </em><em>x</em><em> </em><em>and</em><em> </em><em>seeing</em><em> </em><em>if</em><em> </em><em>they</em><em> </em><em>are</em><em> </em><em>equal</em>

<em>For</em><em> </em><em>example</em>

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