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lana66690 [7]
3 years ago
8

Finding the difference between 827 and 533

Mathematics
1 answer:
atroni [7]3 years ago
8 0
To find the difference of numbers, all you have to do is subtract them

827 - 533
Subtract
Final Answer: The difference between 827 and 533 is 294
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A jar contains red and green balls. A person reaches in and randomly selects a ball to indicate the number of points earned or l
user100 [1]

Answer:

There would have to be -6

Step-by-step explanation:

5 0
3 years ago
Can someone explain this? :)
Alchen [17]

I'll do part (a) to get you started.

The angle 'a' pairs up with the 123 degree angle as a corresponding angle pair. Due to the parallel lines, the corresponding angles are congruent. Therefore a = 123.

We also see that b = 123 as well since a = b (they are vertical angles).

Notice how angle c is adjacent to the 123 degree angle. These two angles form a straight line, so they must add to 180 degrees.

c+123 = 180

c = 180-123

c = 57

-------------------------

To summarize, we have these three angles

a = 123

b = 123

c = 57

6 0
3 years ago
Read 2 more answers
How do you use equivalent fractions to compare the fractions in each pair
Alenkasestr [34]
Firstly you need to to reduce to a common denominator by multiplYing the whole fraction. This way you have to multiply 4/5 by 2 (both numerator and denominator). so 4/5 = 8/10. And now you have 8/10 and 9/10. You compare only numerators. This way you have 8/10 <9/10. Same goes for 2/3 and 5/8. Only here you need to multiply both fractions. The common denominator here is 24. So you have to multiply 2/3 by 8 and 5/8 by 3. You now have to compare 16/24 and 15/24. 16/24>15/24.
8 0
3 years ago
I WILL AWARD BRAINLIEST!! PLEASE HELP!!
den301095 [7]

Answer:

1) x = (a+c)/b

2) The equation is correct no matter what value x takes.

Step-by-step explanation:

1) a−(a+b)x=(b−a)x−(c+bx)

<=> a - ax - bx = bx - ax - c - bx

<=> a - ax - bx - (bx - ax - c - bx) = 0

<=> a - ax - bx - bx + ax + c + bx = 0

<=> a - ax + ax - bx - bx + bx + c = 0

<=> a - bx + c = 0

<=> bx = a + c

If b ≠ 0, x = (a+c)/b

2) 2(3x−5a)+9(2a−7b)+3(5a−2x)=0

<=> 2×3x + 2×(-5a) + 9×2a + 9× (-7b) + 3×5a + 3×(-2x) = 0

<=> 6x -10a + 18a - 63b + 15a - 6x = 0

<=> (6x - 6x) + (15a - 10a + 18a) - 63b = 0

<=> 23a - 63b = 0

<=> 23a = 63b

=> a = 63b/23

with all values of x, the equation is correct.

3 0
3 years ago
Read 2 more answers
How to i solve for x in this situation? thank yous.
Lena [83]

i did not understand the question can u explain again i can help u


4 0
3 years ago
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