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Hoochie [10]
3 years ago
9

5.241 divided by 3 please help me​

Mathematics
2 answers:
SOVA2 [1]3 years ago
5 0

Hey Mate!

Your answer is

1.747

Tell me if this helps!<3

maria [59]3 years ago
3 0
The answer to your question is 1.747
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Completely factor the polynomial 8x2 – 24x + 20x – 60.
Katena32 [7]
The answer is -4(11+x).
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3 years ago
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Because the two distributions displayed below have different ranges, they have the different standard deviations.
tigry1 [53]
False, the range is just determined by minising the lowest from the highest, but the variables can still get you the same mean, which can lead to the same standard deviation
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3 years ago
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I need help ASAP <br> Integrated math II
Molodets [167]

Answer:

\boxed{ \bold{ \sf{x = 16}}}

\boxed{ \bold{ \sf{m < AFD = 82}}}

Step-by-step explanation:

\sf{5x + 18 = 3x + 50}

( Being vertically opposite angles)

Vertically opposite angles are always equal.

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S and change it's sign

⇒\sf{5x  - 3x = 50 - 18}

Collect like terms

⇒\sf{2x = 50 - 18}

Subtract 18 from 50

⇒\sf{2x = 32}

Divide both sides of the equation by 2

⇒\sf{ \frac{2x}{2}  =  \frac{32}{2} }

Calculate

⇒\sf{x = 16}

The value of x is 16

Now, let's find value of m<AFD :

\sf{m < afd + 5x + 18 = 180} ( sum of angle in straight line )

plug the value of x

⇒\sf{m < AFD + 5 \times 16 + 18 = 180}

Multiply the numbers

⇒\sf{m < AFD + 80 + 18 = 180}

Add the numbers

⇒\sf{m < AFD + 98 = 180}

Move constant to R.H.S and change it's sign

⇒\sf{m < AFD = 180 - 98}

Subtract 98 from 180

⇒\sf{m < AFD = 82}

Value of m<AFD = 82

Hope I helped!

Best regards!!

3 0
3 years ago
Find the measure of the missing angle. 122,79,90,Z
Alexxx [7]
The total amount of angles in quadrilateral is 360.so:

z=360-(122+79+90)
z=360-291
z=69
7 0
3 years ago
Write a quadratic function for each graph described.
user100 [1]

Answer:

y=2x^2-\frac{4}{3}x-\frac{10}{3}

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

so

we can write the equation of the parabola as

y=a(x+1)(x-\frac{5}{3})

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

40=a(5+1)(5-\frac{5}{3})

40=a(6)(\frac{10}{3})

40=20a\\a=2

substitute

y=2(x+1)(x-\frac{5}{3})

apply distributive property

y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}

see the attached figure to better understand the problem

6 0
3 years ago
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