P= 500. I = 0.04. t=5. plug those numbers into the formula. So 1.04^5 and multiplying it time 500 and the final answer would be 608.33
Answer:
c. 61.25 kg
Step-by-step explanation:
The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean.
a. 15.31 kg
b. 51.40 kg
c. 61.25 kg
d. 80.49 kg
Margin of Error Formula= z × Standard deviation/√n
95% confidence interval = 1.96
Standard deviation = 125kg
n = 16 samples
Margin of error= 1.96 × 125/√16
= 1.96 × 125/4
= 245/4
= 61.25kg
The margin of error in estimating the true mean weight of male baluga whales in the Artic Ocean is 61.25kg
Well if you have 48 pics of flowers and 36 pictures of scenery and you want an equal amount of pictures of the scenery, you want to start out by just seeing what number divides evenly into both, in this case, it is four.
15 can be 15/1 = 30/2
30/2 + 9/2 = 39/2
The least common denominator of 10 and 15 is 30. It's easiest to use trial and error to find the LCD. In this case, just multiply both numbers by 2 and see if that works. Since 15 doesn't go into 20, I tried multiplying 15 by 2 instead, and got 30, which is divisible by 2. If that doesn't work, move on to multiplying them by 3, then 4 four, and so on. However, in this case, it did work, so, since you multiplied 15 by two to get 30, multiply 7 by two to get the fraction 14/30. Then, since you multiplied 10 by 3 to get 30, multiply 2 by 3 to get 6/30. Then, add the two together to get 20/30 and simplify the fraction to 2/3.
2/10 + 7/15 Given.
6/30 + 14/30 LCD.
20/30 Add.
2/3 Simplify.
