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vladimir2022 [97]
3 years ago
14

If ∠MHT measures 143°, what is the measure of ∠THN?

Mathematics
1 answer:
IgorC [24]3 years ago
6 0
Hello,

I suppose N in on the same line as MH
Angles are thus supplementaries
180-143=37°
Answer B
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34x17 partial product
garri49 [273]

34 x 17 = 28 +210+40 + 300=578

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6 Knightmare Give an algorithm to find the number of ways you can place knights on an N by M (M < N) chessboard such that no
JulsSmile [24]

Answer:

Function to return the maximum number of  knights that can be placed on the given chessboard such that no two knights attack each other.

Step-by-step explanation:

In this algorithm it's fully described the maximum number

#include <bits/stdc++.h>  

using namespace std;  

 

int max_knight(int n, int m)  

{  

 

  // Check for corner case #1  

   //If row or column is 1

   if (m == 1 || n == 1) {  

 

       // If yes, then simply print total blocks  

       // which will be the max of row or column  

       return max(m, n);  

   }  

 

   // Check for corner case #2  

   // If row or column is 2  

   else if (m == 2 || n == 2) {  

 

       // If yes, then simply calculate  

       // consecutive 2 rows or columns

       int c = 0;  

       c = (max(m, n) / 4) * 4;  

 

       if (max(m, n) % 4 == 1) {  

           c += 2;  

       }  

       else if (max(m, n) % 4 > 1) {  

           c += 4;  

       }  

       return c;  

   }  

 

  // For general case, just print the  

   // half of total blocks

   else {  

       return (((m * n) + 1) / 2);  

   }  

}  

 

// Driver code  

int main()  

{  

   int n = 4, m = 5;  

 

   cout << max_knight(n, m);  

 

   return 0;  

}

7 0
3 years ago
PLEASE HELP!!
Ivahew [28]

Answer:

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6 0
2 years ago
Which statement is correct?
tatuchka [14]

Answer:

I think it is

A.) AB is perpendicular to MN

Step-by-step explanation:

6 0
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If it costs 9.50 to buy a movie ticket what is the most number of tickets someone can buy for 40.00 and how much money is left o
MaRussiya [10]
4, and two dollars are left.
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