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user100 [1]
3 years ago
10

Round your answer to the nearest hundredth.

Mathematics
2 answers:
Colt1911 [192]3 years ago
6 0

Answer:

33.69

Step-by-step explanation:

Andrej [43]3 years ago
4 0

Answer:

Step-by-step explanation:

tan (?) = 2/3

On the calculator do tan^(-1)=2/3

you get around 33.69 degrees

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For what values of a is the distance between P(a,3) and Q(5,2a) greater than √26
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P(a,3)\ \ \ Q(5,2a)\\\\ PQ=\sqrt{(x_Q-x_P)^2+(y_Q-y_P)^2}\\\\ PQ>\sqrt{26}\\\\\sqrt{(5-a)^2+(2a-3)^2}>\sqrt{26}\\\\\sqrt{25-10a+a^2+4a^2-12a+9}>\sqrt{26}\\\\\sqrt{5a^2-22a+34}>\sqrt{26}\ \ |^{2}\\\\
5a^2-22a+34=26\ \ \ |Subtract\ 26\\\\
5a^2-22a+8=0\ \ \ |Factoring\\\\(a-4)(5a-2)=0\\\\
a=4\ \  or\ \  5a=2\\
a=4\ \ or\ \ a=\frac{2}{5}
6 0
4 years ago
To fit between two windows, the width of a bookshelf must be no greater than 6.5 feet. Mrs. Aguilar purchases a bookshelf that i
expeople1 [14]

Answer:

The bookshelf will fit between the windows with 1 inch remaining.

Step-by-step explanation:

First, I will convert 6.5 feet to inches.

6.5 × 12 = 78 inches

So, there is 78 inches between the windows.

78 - 77 = 1 inch remaining

The bookshelf will fit between the windows with 1 inch remaining.

3 0
4 years ago
Read 2 more answers
As r varies the equation (r −
seropon [69]
I have no idea bro, sorry
7 0
3 years ago
Henry has $ 21.50 to ride the trolley around San Francisco this week. It will cost him $ 0.50 every time he rides. Identify the
dusya [7]

Answer:

The Independent Value is the Amount of Money he has

The Dependent Value is the amount of Times he can Ride the Trolley

Step-by-step explanation:

This is because the cost is taken into account for the amount of times he can ride the trolley but the amount of money he has is not reliant or controlled by another piece of information.

4 0
4 years ago
Joe's annual income has been increasing in the same dollar amount. The first year his income was $15,200, and the 4th year his i
lidiya [134]

Answer:

Therefore 6th year his income was $19,700.

Step-by-step explanation:

Given, Joe's annual income has been increasing in some dollar amount . The first year his income was $15,200 and 4th  year his income was $17,900.

A=$17900, P= $15,200 and n = 3 year

A= P(1+\frac{r}{100} )^n

\Leftrightarrow 17900=15200(1+\frac{r}{100})^3

\Leftrightarrow (1+\frac{r}{100})^3=\frac{17900}{15200}

\Leftrightarrow (1+\frac{r}{100})=(\frac{17900}{15200})^{\frac{1}{3} }

\Leftrightarrow \frac{r}{100}=(\frac{17900}{15200})^{\frac{1}{3} }-1

\Leftrightarrow r=5.60

Let  t^{th} year Joe's income was $19,700.

\therefore 19700=15,200(1+\frac{5.60}{100} )^{t-1}

\Leftrightarrow 1.296= (1+0.056)^{t-1}

\Leftrightarrow 1.296= (1.056)^{t-1}

\Leftrightarrow  log(1.296)= (t-1)log(1.056)

\Leftrightarrow  \frac{log(1.296)}{log(1.056)}= (t-1)

\Leftrightarrow t-1= 4.75

\Leftrightarrow t= 4.75+1

\Leftrightarrow t = 5.75 ≈6

Therefore 6th year his income was $19,700.

8 0
3 years ago
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