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coldgirl [10]
3 years ago
15

Consider that point A is reflected across the x-axis. What is the distance between point A and the point of its reflection?

Mathematics
1 answer:
liraira [26]3 years ago
6 0

Answer:

It would be 2 x the absolute value of the y coordinate.

Step-by-step explanation:

Example:

(5,-3)

Absolute value of y-coordinate is 3 and distance would equal 2 x 3 = 6 units apart.

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Teddy has 23 boxes of juice packed and plans to pack 3 additional boxes each hour. Charley has 7 boxes packed and plans to pack
Damm [24]

Answer:

8 hours

Step-by-step explanation:

23 + 3x = 5x + 7

First would be to subtract 3x from both sides to maintain equality.

23 = 2x +7

Then subtract 7 from both sides

16 = 2x

Finally divide by 2 from both sides to solve for x

8 = x

3 0
3 years ago
The equation c = 2r + 8 represents the cost of an amusement park. C represents the total cost, r is the cost per ride and 8 is t
iris [78.8K]

Answer:

yes there is because if you do

6 0
3 years ago
Independent random samples from two regions in the same area gave the following chemical measurements (ppm). Assume the populati
Basile [38]

Answer:

d. The interval contains only negative numbers. We cannot say at the required confidence level that one region is more interesting than the other.

Step-by-step explanation:

Hello!

You have the data of the chemical measurements in two independent regions. The chemical concentration in both regions has a Gaussian distribution.

Be X₁: Chemical measurement in region 1 (ppm)

Sample 1

n= 12

981 726 686 496 657 627 815 504 950 605 570 520

μ₁= 678

σ₁= 164

Sample mean X[bar]₁= 678.08

X₂: Chemical measurement in region 2 (ppm)

Sample 2

n₂= 16

1024 830 526 502 539 373 888 685 868 1093 1132 792 1081 722 1092 844

μ₂= 812

σ₂= 239

Sample mean X[bar]₂= 811.94

Using the information of both samples you have to determina a 90% CI for μ₁ - μ₂.

Since both populations are normal and the population variances are known, you can use a pooled standard normal to estimate the difference between the two population means.

[(X[bar]₁-X[bar]₂)±Z_{1-\alpha /2}* \sqrt{\frac{Sigma^2_1}{n1}+\frac{Sigma^2_2}{n_2}  }]

Z_{1-\alpha /2}= Z_{0.95}= 1.648

[(678.08-811.94)±1.648*\sqrt{\frac{164^2}{12}+\frac{239^2}{16}  }]

[-259.49;-8.23]ppm

Both bonds of the interval are negative, this means that with a 90% confidence level the difference between the population means of the chemical measurements of region 1 and region 2 may be included in the calculated interval.

You cannot be sure without doing a hypothesis test but it may seem that the chemical measurements in region 1 are lower than the chemical measurements in region 2.

I hope it helps!

6 0
4 years ago
Solve for x, if. 3(x-8)-5=9(x+2)+1 the answer is 7.166 but i don't know how they got it
djverab [1.8K]
The answer and workings are in the document below. Please open it up in a new window to see it in full.

7 0
3 years ago
Read 2 more answers
Can someone please help with this asap
Alecsey [184]

there's nothing in your screen

6 0
4 years ago
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