An electromagnetic wave traveling in a

What is the magnitude of the momentum of a 11kg object moving at 2.2 m/s?

tangare [24]

Answer:

<h3>The answer is 24.2 kgm/s</h3>

Explanation:

The momentum of an object can be found by using the formula

<h3>momentum = mass × velocity</h3>

From the question

mass = 11 kg

velocity = 2.2 m/s

We have

momentum = 11 × 2.2

We have the final answer as

Hope this helps you

4 0

3 years ago

A stationary sub uses sonar to send a 1.18x10^3 hertz sound wave through ocean water. The reflected sound wave from the flat oce

vampirchik [111]

Answer:

a) v = 1524.7 m/s

b) T = 8.47*10^-4 s

λ = 1.29 m

Explanation:

a) First, in order to calculate the speed of the sound wave, you take into account that the velocity is constant, then, you use the following formula:

$v=\frac{d}{t}$

d: distance traveled by the sound wave, which is twice the distance to the ocean bottom = 2*324 m = 648 m

t: time that sound wave takes to return to the sub = 0.425

$v=\frac{648m}{0.425s}=1524.7\frac{m}{s}$

hence, the speed of the sound wave is 1524.7 m/s

b) Next, with the value of the velocity of the wave you can calculate the wavelength of the wave, by using the following formula:

$v=\lambda f\\\\\lambda=\frac{v}{f}$

f: frequency = 1.18*10^3 Hz

$\lambda=\frac{1524.7m/s}{1.18*10^3s^{-1}}=1.29m$

And the period is:

$T=\frac{1}{f}=\frac{1}{1.18*10^3s^{-1}}=8.47*10^{-4}s$

hence, the wavelength and period of the sound wave is, respectively, 1.29m and 8.47*10^-4 s

5 0

3 years ago

We are given the description of an enclosure that has fencing on 3 sides and can use 3,056 yards of fencing. We are to find the

shusha [124]

Answer:

The sum of the lengths of the sides is 2292 yards and the sum of the lengths of the triangle is 3056 yards

Explanation:

Since y represents the length of fence that is opposite (parallel) to the river and x represent the length of fence perpendicular to the river.

Therefore since we can use 3,056 yards of fencing

Side perpendicular to the river = x and,

Side opposite to the river = y = 3056 - 2x

The area of the rectangle formed (A) = Perpendicular side × Parallel side

∴ A = x(3056 - 2x) = 3056x - 2x²

A = 3056x - 2x²

To maximize the area, A' (dA/dx) = 0

∴ A' = 3056 - 4x = 0

3056 - 4x = 0

4x = 3056

x = 764 yards

y = 3056 - 2x = 3056 - 2(764) = 1528 yards.

Side perpendicular to the river = 764 yards and,

Side opposite to the river = 1528 yards

The sum of the lengths of the sides = 764 + 1528 = 2292 yard and the sum of the lengths of the triangle = 764 + 764 + 1528 = 3056 yards

5 0

3 years ago

How long does it take (in minutes) for light to reach mercury from the sun, a distance of 6.02 × 107 km?

Ksju [112]

Light travels at a speed of:
$c=3 \cdot 10^8 m/s$
The distance between Mercury and Sun is $S=6.02 \cdot 10^7 km=6.02 \cdot 10^{10} m$ , so the time it takes is
$t= \frac{S}{c}= \frac{6.02 \cdot 10^{10} m}{3 \cdot 10^8 m/s} =200.7 s$
if we want to convert this into minutes, keeping in mind that 1 min = 60 seconds, we should divide this value by 60:
$t= \frac{200.7 s}{60 s/min}=3.34 min$

6 0

4 years ago

Read 2 more answers

If a soccer ball takes 20 seconds to roll 10 meters, what is the average speed of the soccer ball?

xxTIMURxx [149]

2 Seconds per 1 meter

5 0

3 years ago