Magnitude of acceleration = (change in speed) / (time for the change) .
Change in speed = (ending speed) - (starting speed)
= zero - (43 m/s)
= -43 m/s .
Magnitude of acceleration = (-43 m/sec) / (0.28 sec)
= (-43 / 0.28) (m/sec) / sec
= 153.57... m/s²
= 1.5... x 10² m/s² .
Answer:
D. the distance and direction to the water fountain
Explanation:
To describe the position of a water fountain relative to where one is standing, the distance and direction to the water fountain must be known.
This quantity is known as the displacement.
- Displacement is a vector quantity with both magnitude and direction.
- To specify the magnitude of a displacement, we use the length of path and in this case the height or sometimes the distance.
- The direction attribute distinguishes distance from displacement
- The perfect quantity to solve this problem is the displacement and it specifies the distance of the path and the direction traveled.
Answer:
In nuclear physics and nuclear chemistry, nuclear fission is a nuclear reaction or a radioactive deficiency process in which the nucleus of an atom split into 2 smaller, lighter nuclei.
Answer:
v = 0.42m/s
Explanation:
In order o calculate the linear speed of the point at the border of the wheel, you first take into account that the total acceleration of such a point is given by:
(1)
atotal: total acceleration = 1.2m/s^2
ar: radial acceleration of the wheel
at: tangential acceleration
The tangential acceleration is also given by:
(2)
r: radius of the wheel = (40cm/2 )= 20cm = 0.2m
α: angular acceleration = 4.0rad/s^2
You replace the expression (2) into the expression (1) and solve for the radial acceleration:

Next, you use the following formula for the radial acceleration and solve for the linear speed:

The linear speed of the point at the border of the wheel is 0.42m/s