2 years ago

What is the product of (2p+7)(3p^2 +4p-3)

Mathematics

1 answer:

-BARSIC- [3]2 years ago

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Answer:

6p^3 + 29p^2 + 22p - 21

Step-by-step explanation:

You can find the product of the expression using the distributive property. The distributive property multiplies the terms of one parenthesis into each term in the other parenthesis. Simplify the product that results by combining like terms or terms which have the same base and exponent.

(2p+7)(3p^2 +4p-3)

6p^3 + 21p^2 + 8p^2 + 28p -6p - 21

6p^3 + 29p^2 + 22p - 21

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K(k + 1)(k + 2) – 3k(k + 1)<br><br> Need a step-by-step guide on how to factor this completely

Dimas [21]

Answer:

Step-by-step explanation:

k(k+1)(k+2) - 3k(k+1)

k and (k+1) are common to both terms.

k(k+1)(k+2) - 3k(k+1) = k(k+1)[(k+2) - 3] = k(k+1)(k-1)

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