The shadow of the tree is about 17.955 feet long.
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
I'd do a little more than 77minutes for the 6and 7for if you could have it on 77and but you could have it in your head
Answer:
CU = 117
Step-by-step explanation:
Since the triangles are similar then the ratios of corresponding sides are equal, that is
= 
substituting in values to the ratios
=
( cross- multiply )
24(36x - 1) = 3432 ( divide both sides by 24 )
36x - 1 = 143 ( add 1 to both sides )
36x = 144 ( divide both sides by 36 )
x = 4
CU = 36x - 1 - 26 = (36 × 4) - 27 = 144 - 27 = 117
12-x(5-4k)=y
12-y=x(5-4k)
12-y/(5-4k)=x