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Georgia [21]
3 years ago
15

Triangle DEF has sides with lengths of 6, 11, and 13 units. Determine whether this triangle is a right triangle. Show all work n

ecessary to justify your answer. A right triangle has a hypotenuse with a length of 25. The lengths of the legs are whole numbers. What could be possible lengths of the legs?
Mathematics
1 answer:
mario62 [17]3 years ago
8 0

Answer:

Triangle DEF is not a right triangle ; possible lengths are 20 & 15

Step-by-step explanation:

For right triangle;

the sum of the square of the two adjacent sides must equal the square of the hypotenus.

Therefore, (6^2)+(11^2)≠(13^2).

the possible length are 20 & 15 because

(20^2)+(15^2)=(25^2)

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Answer:

a) Let \frac{a}{b}=\frac{-1}{x^2}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

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b)

Let \frac{a}{b}=\frac{1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x^2}.

Observe that

\frac{a}{b}-\frac{c}{d}=\frac{1}{x}-\frac{1}{x^2}=\frac{x^2-x}{x^3}=\frac{x(x-1)}{xx^2}=\frac{x-1}{x^2}

c)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{1}{x}.

Observe that

\frac{a}{b}*\frac{c}{d}=\frac{x-1}{x}*\frac{1}{x}=\frac{(x-1)1}{x*x}=\frac{x-1}{x^2}

d)

Let \frac{a}{b}=\frac{x-1}{x}, \text{ and } \frac{c}{d}=\frac{x}{1}.

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Answer:

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Step-by-step explanation:

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
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Let

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<h3>ATQ </h3>

{:}\leadsto\sf x+x+12=36

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