Prove the divisibility of the following numbers: 8^10−8^9−8^8 by 55
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A quadratic equation in standard form that can be used to determine the value of x is - 8x - 65 = 0.
The Factor of the equation from Part B is (x - 13)(x + 5) and the possible solutions to the equation is x = 13 or -5.
The value for the second number is 5
<h3>Word Problem Leading To Quadratic Equation.</h3>The general formula for quadratic equation in a in standard form is
a + bx + c = 0
Given that the difference between two integers is 8
Let the two integers = x and y,
and their product is 65. If the larger of the two numbers is x. Then,
x - y = 8 and xy = 65
Since we are looking for the value of x, make y the subject of formula in the first equation.
y = x - 8
Substitute y in the second equation.
x(x - 8) = 65
- 8x - 65 = 0
- 13x + 5x - 65 = 0
(x - 13)(x + 5) = 0
x = 13 or -5
We will ignore -5 since x is the larger number.
To get y Substitute x in the second equation.
xy = 65
13y = 65
y = 65/13
y = 5
Therefore, a quadratic equation in standard form that can be used to determine the value of x is - 8x - 65 = 0. The Factor of the equation from Part B is (x - 13)(x + 5) and the possible solutions to the equation is x = 13 or -5. The value for the second number is 5
Learn more about Quadratic Equation here: brainly.com/question/25841119
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Answer:
x =
Step-by-step explanation:
To solve for x, we need to isolate it [get it alone on one side]
We should start by simplifying (combining the like-terms of our equation):
5 + 5 = 5x + 5 - 2
10 = 5x + 3
- 3 - 3 (subtract 3 from both sides to isolate x)
7 = 5x
÷5 ÷5 (divide both sides by 5 to find "1"x)
So, x =
(x = 7/5)
hope this helps!!