Answer:
y=-3x+3..........(1)
6x+2y=6
putting value of y
6x+2(-3x+3)=6
6x-6x+6=6
o=0
sorry I do not get answer
The slope, y-intercept and the equation of the following graph are as follows:
1(a)
slope : 1
y-intercept: 2
Equation: y = x + 2
(b)
slope : - 1 / 3
y-intercept: - 1
Equation: y = - 1 / 3x - 1
2.
(a)
slope : 3 / 4
y-intercept: 5 / 4
Equation: y = 3 / 4 x + 5 / 4
(b)
slope : - 3 / 2
y-intercept: 1 / 2
Equation: y = - 3 / 2 x + 1 / 2
<h3 />
<h3>Slope intercept equation</h3>
where
m = slope
b = y-intercept
Therefore lets find the slope, y-intercept and equation of the following graph.
1.
(a)
(0, 2)(1, 3)
m = 3 - 2 / 1 - 0 = 1
b = 2
y = x + 2
(b)
(0, -1)(-3, 0)
m = 0 + 1 / -3 - 0 = - 1 / 3
b = -1
y = - 1 / 3x - 1
2.
(a)
(1, 2)(-3, -1)
m = -1 - 2 / -3 - 1 = 3 / 4
2 = 3 / 4 (1) + b
b = 2 - 3 / 4 = 5 / 4
y = 3 / 4 x + 5 / 4
3.
(b)
(-3, 5)(1, -1)
m = - 1 - 5 / 1 + 3 = - 6 / 4 = - 3 / 2
-1 = - 3 /2 (1) + b
b = -1 + 3 / 2 = 1 /2
y = - 3 / 2 x + 1 / 2
learn more on y-intercept here: brainly.com/question/2833377?referrer=searchResults
Answer:
1 commutative
2 identity
3 associative
4 identity
5 associative
Step-by-step explanation:
The graph that represents the given linear function is attached below.
We are given a function. A function connects an input with an output. It is analogous to a machine with an input and an output. And the outcome is somehow connected to the input. The equation is linear in nature. It represents a straight line. The equation is given below.
(y - 4) = (4/3)(x - 2)
A line's general equation in slope-intercept form is y = mx + c. We will convert the given equation into this form.
y - 4 = (4/3)x - 8/3
y = (4/3)x - 8/3 + 4
y = (4/3)x + 4/3
The slope of the given equation is 4/3. The y-intercept for the given equation is 4/3.
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Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: motor skills of a sober subject.
n= 20
X[bar]= 37.1
S= 3.7
The claim is that the average score for all sober subjects is equal to 35.0, symbolically: μ= 35.0
The hypotheses are:
H₀: μ = 35.0
H₁: μ ≠ 35.0
α: 0.01
The statistic to use, assuming all conditions are met, is a one sample t- test
![t= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } } ~t_{n-1}](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BS%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~t_%7Bn-1%7D)

This test is two-tailed, meaning, the rejection region is divided in two and you'll reject the null hypothesis to low values of t or to high values of t:


The decision rule using this approach is:
If
≤ -2.861 or if
≥ 2.861, you reject the null hypothesis.
If -2.861 <
< 2.861, you do not reject the null hypothesis.
The value is within the non rejection region, the decision is to not reject the null hypothesis.
I hope this helps!