Write the expression as a square of a monomial 121a^6

1 answer:

Nutka1998 [239]3 years ago

5 0

The square root of 121 is 11. The square toot of a^6 is a^3. Therefore 121a^6 can be expressed as (11a^3)^2, and 11a^3 is a monomial since it is a single term with nothing added or subtracted to it or from it. So 121a^6 as a squared monomial is (11a^3)^2.

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Find the exponential function that satisfies the given conditions: Initial value = 64, decreasing at a rate of 0.5% per week

mrs_skeptik [129]

Answer:

Step-by-step explanation:

An exponential function is of the form

$y=ab^x$

where a is the initial value and b is the growth/decay rate. Our initial value is 64. That's easy to plug in. It goes in for a. So the first choice is out. Considering b now...

If the rate is decreasing at .5% per week, this means it still retains a rate of

100% - .5% = 99.5%

which is .995 in decimal form.

b is a rate of decay when it is greater than 0 but less than 1; b is a growth rate when it is greater than 1. .995 is less than 1 so it is a rate of decay. The exponential function is, in terms of t,

$f(t) = 64(.995)^t$