Find the slope of the line that passes through points (3,2) and (-2,-2)

Sarah’s company sells bracelets and rings. Her first customer buys 3 bracelets and 10 rings, spending a total of $48. Her second

timofeeve [1]

Sarah charges $6.00 for one bracelet.

We know that a collection of one or more linear equations containing the same variables is known as a system of linear equations in mathematics.

Let Sarah charges $x and $y for one bracelet and one ring respectively.

Since her first customer spends $48 on 3 bracelets and 10 rings, we can write it as

3x + 10y = 48 ...(1)

Since her second customer spends $54 on 7 bracelets and 4 rings, we can write it as

7x + 4y = 54 ...(2)

Now, we have to solve this system of linear equations.

Multiplying (1) by 2, 6x + 20y = 96 ...(3)

Multiplying (2) by 5, 35x + 20y = 270 ...(4)

Subtracting (3) from (4), 35x + 20y - 6x - 20y = 270 - 96

i.e. 29x = 174

i.e. x = 174/29 = 6

Therefore we can conclude that Sarah charges $6 for one bracelet. Option B is correct.

Know more about the system of linear equations here -

brainly.com/question/27664510

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3 0

2 years ago

A tree stands 22 feet tall and is 382 feet from a building. The tree casts a shadow that is 40 feet long. How tall is the buildi

Norma-Jean [14]

Yes, you are correct to use proportions because they are similar triangles.

7 0

3 years ago

Task is to construct two brick columns of the dimensions shown on which an iron gate will eventually be hung. Because the bricks

lidiya [134]

Answer:

224 in²

Step-by-step explanation:

16 × 14 = 224 in²

5 0

3 years ago

A thin metal plate, located in the xy-plane, has temperature T(x, y) at the point (x, y). Sketch some level curves (isothermals)

Sophie [7]

Answer:

Step-by-step explanation:

Given that:

$T(x,y) = \dfrac{100}{1+x^2+y^2}$

This implies that the level curves of a function(f) of two variables relates with the curves with equation f(x,y) = c

here c is the constant.

$c = \dfrac{100}{1+x^2+2y^2} \ \ \--- (1)$

By cross multiply

$c({1+x^2+2y^2}) = 100$

$1+x^2+2y^2 = \dfrac{100}{c}$

$x^2+2y^2 = \dfrac{100}{c} - 1 \ \ -- (2)$

From (2); let assume that the values of c > 0 likewise c < 100, then the interval can be expressed as 0 < c <100.

Now,

$\dfrac{(x)^2}{\dfrac{100}{c}-1 } + \dfrac{(y)^2}{\dfrac{50}{c}-\dfrac{1}{2} }=1$

This is the equation for the family of the eclipses centred at (0,0) is :

$\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}=1$

$a^2 = \dfrac{100}{c} -1 \ \ and \ \ b^2 = \dfrac{50}{c}- \dfrac{1}{2}$

Therefore; the level of the curves are all the eclipses with the major axis:

$a = \sqrt{\dfrac{100 }{c}-1}$ and a minor axis $b = \sqrt{\dfrac{50 }{c}-\dfrac{1}{2}}$ which satisfies the values for which 0< c < 100.

The sketch of the level curves can be see in the attached image below.

7 0

3 years ago

Here is a picture of a cube, and the net of this cube. What is the surface area of this cube? Enter your answer in the box. ft²

kobusy [5.1K]

The surface area of the cube is 1536 square feet because (16×16)×6=1536 square feet. Hope it help!

3 0

3 years ago

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