Answer:
108 since in order to find out the maximum amount, we have to find the volume of the full pan, which is found by the formula shown below:
Vbrownie batter=L×W×H=9×8×1.5=108cubic inches
<span><span>2<span>(<span><span>3x</span>−4</span>)</span></span>=<span><span>3x</span>+1
</span></span>Step 1: Simplify both sides of the equation.
<span><span>2<span>(<span><span>3x</span>−4</span>)</span></span>=<span><span>3x</span>+1</span></span><span>Simplify: (Show steps)</span><span><span><span>6x</span>−8</span>=<span><span>3x</span>+1
</span></span>Step 2: Subtract 3x from both sides.
<span><span><span><span>6x</span>−8</span>−<span>3x</span></span>=<span><span><span>3x</span>+1</span>−<span>3x</span></span></span><span><span><span>3x</span>−8</span>=1
</span>Step 3: Add 8 to both sides.
<span><span><span><span>3x</span>−8</span>+8</span>=<span>1+8</span></span><span><span>3x</span>=9
</span>Step 4: Divide both sides by 3.
<span><span><span>3x</span>3</span>=<span>93
</span></span><span> answer : x=<span>3
hope this helps!</span></span>
Answer:
A+6+A = 20
A = 7
Step-by-step explanation:
J = number of problems Juana completed
A = number of problems Andy completed
J+A=20
J = A + 6
Replace J with A+6 in the first equation
A+6+A = 20
2A +6 = 20
Subtract 6 from each side
2A +6-6 = 20-6
2A =14
Divide by 2
2A/2 = 14/2
A = 7
I'm reading this as

with

.
The value of the integral will be independent of the path if we can find a function

that satisfies the gradient equation above.
You have

Integrate

with respect to

. You get


Differentiate with respect to

. You get
![\dfrac{\partial f}{\partial y}=\dfrac{\partial}{\partial y}[x^2e^{-y}+g(y)]](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%20f%7D%7B%5Cpartial%20y%7D%3D%5Cdfrac%7B%5Cpartial%7D%7B%5Cpartial%20y%7D%5Bx%5E2e%5E%7B-y%7D%2Bg%28y%29%5D)


Integrate both sides with respect to

to arrive at



So you have

The gradient is continuous for all

, so the fundamental theorem of calculus applies, and so the value of the integral, regardless of the path taken, is