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3 years ago

Fernando needs a total of 6 2/3 cups of flour to make 5 batches of bread. How much flour is needed for each batch of bread?

Mathematics

2 answers:

AysviL [449]3 years ago

7 0

Answer:d is the correct answer

Step-by-step explanation:just did the assinment on edenuity

erastovalidia [21]3 years ago

6 0

Answer:

One batch of bread requires 1 1/3 cups of flour

<h3>Step by step equations:</h3>

6 2/3= 20/3

20/3 ÷ 5/1 = 20/3 x 1/5

20/3 x 1/5 = 20/15

20/15 simplified is 1 1/3

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A varies inversely with B.<br> When A is 0.25, B is 4.<br> Find the value of B when A is 5.

andrew-mc [135]

Answer:80

Step-by-step explanation:if you multiply a times 20 to get 5, you have to multiply b times 20 to get 80

7 0

2 years ago

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Are the ratios 3:4 and 2:5 equivalent?<br> yes or no

olya-2409 [2.1K]

Answer:

Step-by-step explanation:

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2 years ago

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The variable Z is directly proportional to X. When X is 12, Z has the value 228. What is the value of Z when X = 18

Kisachek [45]

Here, z = kx

k = z/x
k = 228/12
k = 19

So, when x = 18,
z = 19 * 18
z = 342

In short, Your Answer would be: 342

Hope this helps!

8 0

3 years ago

A rectangular parking lot has an area of 15,000 feet squared, the length is 20 feet more than the width. Find the dimensions

faust18 [17]

Dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet

<h3><u>Solution:</u></h3>

Given that

Area of rectangular parking lot = 15000 square feet

Length is 20 feet more than the width.

Need to find the dimensions of rectangular parking lot.

Let assume width of the rectangular parking lot in feet be represented by variable "x"

As Length is 20 feet more than the width,

so length of rectangular parking plot = 20 + width of the rectangular parking plot

=> length of rectangular parking plot = 20 + x = x + 20

<em><u>The area of rectangle is given as:</u></em>

$\text {Area of rectangle }=length \times width$

Area of rectangular parking lot = length of rectangular parking plot $\times$ width of the rectangular parking

$\begin{array}{l}{=(x+20) \times (x)} \\\\ {\Rightarrow \text { Area of rectangular parking lot }=x^{2}+20 x}\end{array}$

But it is given that Area of rectangular parking lot = 15000 square feet

$\begin{array}{l}{=>x^{2}+20 x=15000} \\\\ {=>x^{2}+20 x-15000=0}\end{array}$

Solving the above quadratic equation using quadratic formula

<em><u>General form of quadratic equation is </u></em>

${ax^{2}+\mathrm{b} x+\mathrm{c}=0$

And quadratic formula for getting roots of quadratic equation is

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

In our case b = 20, a = 1 and c = -15000

Calculating roots of the equation we get

$\begin{array}{l}{x=\frac{-(20) \pm \sqrt{(20)^{2}-4(1)(-15000)}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{400+60000}}{2 \times 1}} \\\\ {x=\frac{-(20) \pm \sqrt{60400}}{2}} \\\\ {x=\frac{-(20) \pm 245.764}{2 \times 1}}\end{array}$

$\begin{array}{l}{=>x=\frac{-(20)+245.764}{2 \times 1} \text { or } x=\frac{-(20)-245.764}{2 \times 1}} \\\\ {=>x=\frac{225.764}{2} \text { or } x=\frac{-265.764}{2}} \\\\ {=>x=112.882 \text { or } x=-132.882}\end{array}$

As variable x represents width of the rectangular parking lot, it cannot be negative.

=> Width of the rectangular parking lot "x" = 112.882 feet

=> Length of the rectangular parking lot = x + 20 = 112.882 + 20 = 132.882

Hence can conclude that dimension of rectangular parking lot is width = 112.882 feet and length = 132.882 feet.

3 0

3 years ago

The surface area of rectangular prism is 48 ft.². The area of its front is 4 ft.², and the area of one side is 10 ft.². What is

DaniilM [7]

I think the answer is 20.

3 0

3 years ago