Question

Assume that the probability of a being born with Genetic Condition B is p = 1/60. A study looks at a random sample of 33 volunteers. Find the most likely number of the 33 volunteers to have Genetic Condition B. (Round answer to one decimal place.)

Answer 1

Answer:

The expected number of volunteers in the sample with Genetic condition B is 0.6.

Step-by-step explanation:

The probability of a being born with Genetic Condition B is p = 1/60 = 0.017.

Find the most likely number of the 33 volunteers to have Genetic Condition B.

We can calculate as if it was a binomial distribution, with sample size n=33 and p=0.017.

The expected value of a binomial distribution random variable is calculated as:

$E(x)=np=33*0.017=0.55\approx0.6$

The expected number of volunteers in the sample with Genetic condition B is 0.6.