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3 years ago

HELP PICTURE IS SHOWN

Mathematics

1 answer:

Triss [41]3 years ago

4 0

The picture of graph c would be the right one.

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Hi..can anyone help me.. I really just want to know how can you do it.. I want to learn because I have more examples.. can anyon

Bumek [7]

Sorry I can’t help with this one

5 0

3 years ago

If a bacteria population starts with 80 bacteria and doubles every four hours, then the number of bacteria after t hours is n =

Over [174]

Answer:

Step-by-step explanation:

given that a bacteria population starts with 80 bacteria and doubles every four hours,

The function representing the number of bacteria after t hours

= $n=f(t) = 80*2^{\frac{t}{4} }$

We are to find the inverse of the function

i.e. we must make t = g(n) where g is a function of n.

Take log on both sides.

$ln n =ln80+\frac{t}{4} ln 2\\\frac{t}{4} =\frac{ln\frac{n}{80} }{ln 2} \\t = 4\frac{ln\frac{n}{80} }{ln 2}$

this is the inverse function.

8 0

3 years ago

A car salesman had $65100 in total monthly sales last month. He made $1953 in commission from those sales. What is the salesmans

konstantin123 [22]

Answer:

Step-by-step explanation:

In order to find out the percent in commissions a car salesman received, you need to divide $1953 by $65100. The result is .03, which translates to 3%.

Hope that helps!

6 0

3 years ago

Mae Ling earns a weekly salary of $300 plus a 6.0% commission on sales at a gift shop. How much would she make in a work week if

hram777 [196]

Answer:

546

Step-by-step explanation:

300 + (4100*.06)

300 + 246

546

7 0

2 years ago

The radioactive element americium-241 has a half-life of 432 years. How many years will it take a 10 gram mass of americium-241

geniusboy [140]

<h2>Answer: 816 years</h2>

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u />

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=2.7g$ is the final amount of the material

$A_{o}=10g$ is the initial amount of the material

$t$ is the time elapsed (the quantity we are asked to find)

$h=432y$ is the half life of americium-241

Knowing this, let's find $t$ from (1):

$2.7g=(10g).2^{\frac{-t}{432y}}$

$\frac{2.7g}{10g}=2^{\frac{-t}{432y}}$

$0.27g=2^{\frac{-t}{432y}}$

Applying natural logarithm in both sides:

$ln(0.27g)=ln(2^{\frac{-t}{432y}})$

$-1.309=-\frac{t}{432y}ln(2)$

$-t=\frac{(-1.309)(432y)}{0.693}$

<u></u>

<u>Finally:</u>

$t=816y$

3 0

3 years ago