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Ainat [17]
3 years ago
14

Factor 3x^2y^2 − 2xy^2 − 8y^2. Show your work.

Mathematics
1 answer:
mr Goodwill [35]3 years ago
5 0

1) Look for common factors. You see that y^2 is a factor of every term so you can remove it to get

... = (y^2)(3x^2 -2x -8)

The quadratic in x can be factored by your favorite method. There is one called by various names that has you look for factors of (3)(-8) that add to (-2). When the quadratic is written as ax^2+bx+c, you're looking for factors of the product "ac" that add to "b". Of course, you know that

... -24 = -24*1 = -12*2 = -8*3 = -6*4

the last factor pair shown here has a sum of -2, so our factorization is

... = (y^2)(3x -6)(3x +4)/3 . . . . . the "a" coefficient is repeated in each factor (at first), then divided out

... = (y^2) (x -2) (3x +4)


2) You recognize this expression to be of the form

... (x +a)^2 = x^2 +2ax + a^2

where a=5. As a result, you know the factorization is

... = (x +5)^2


3) You recognize this expression to be the difference of squares, so you know the factorization is

... a^2 - b^2 = (a -b)(a +b)

where a=x and b=6. As a result, you know the factorizatin is

... = (x -6) (x +6)

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kramer

If the solution is blue-green, this indicates that some copper is still present in the solution and that not all of it has precipitated. Expect it to be too low because you will have less mass.

With very few exceptions, all copper(I) (cuprous) compounds are diamagnetic and colorless. Cu2O, Cu2Cl2, and cuprous sulfide are a few of the significant commercial compounds of copper(I) (Cu2S).

The molar mass of the element copper is determined by looking at its average atomic mass, which is 63.55 AMU on the periodic table. Since it is also our molar mass, we will now put it in a different unit: grams over moles (63.55 gmol). That is copper's molar mass.

If the solution is blue-green, there is still copper in the solution and not all of it has precipitated. Because you will have less bulk, anticipate it to be too low.

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3 0
1 year ago
Rachel and Hugo sorted 236 crayons into boxes for a local arts project. Each box had 10 crayons. How many crayons were left over
Kryger [21]
This is a simple division problem. Since there are 236 crayons, in groups of ten, there will be 6 left over because there is a 6 in the ones place. 
8 0
3 years ago
Read 2 more answers
Helpppp pleaseee X•1 + x/1=
dem82 [27]

x * 1 + x/1 =

x + x =

2x

6 0
3 years ago
Can someone help and explain ? thank you !
AfilCa [17]
\sf Hello!

\sf y = 2x^{2} + 4x - 3

\sf Discriminant :

= \sf b^{2} - 4ac

= \sf (4)^{2} - 4.(2).(-3)

= \sf 16 - (-24)

= \sf 16 + 24 = \sf 40

\sf Since,
\sf D \:is\:Greater\: than\: 0.

\sf Roots\: are\: Real\: and\: Distinct

\sf Hence,

\sf y = 2x^{2} + 4x - 3\: have\: A.\: Two\: real\: roots

~ \sf iCarl
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3 years ago
In his restaurant, Manuel is making 'Sandria', a drink made from red juice and iced soda water, mixed in the ratio 2:3. Manuel u
Ivahew [28]
2:3
10:_
2*5=10
3*5=15
a) 15 litres of soda water
b) 10+15 = 25 litres
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3 years ago
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