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3 years ago

Can help me with this Please?

Mathematics

1 answer:

pentagon [3]3 years ago

7 0

Answer:

where's the question at ?

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t takes Phillip 7 hours to proof a chapter of Hawkes Learning Systems' Intermediate Algebra book and it takes Kim 3 hours. How l

Leya [2.2K]

Answer:

2.1 hrs

Step-by-step explanation:

In 1 hr, Phillip would have proofed 1/7 of the chapter. In 1 hr, Kim would have proofed 1/3 of the chapter. So, together in 1 hr, they would have proofed 10/21 of the chapter. So, it would take 21/10 or 2.1 hrs to proof the whole chapter together.

5 0

4 years ago

Krystal puts three pencils in order from longest to shortest what is a fast way to order the same pencils from shortest to longe

Verdich [7]

Swap the shortest and longest pencil's places. You don't have to move the middle pencil.

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4 years ago

Read 2 more answers

Find the limit of the function algebraically.

ArbitrLikvidat [17]

$\bf \lim\limits_{x\to -10}~\cfrac{x^2-100}{x+10}\implies \cfrac{\stackrel{\textit{difference of squares}}{x^2-10^2}}{x+10}\implies \cfrac{(x-10)(\underline{x+10})}{\underline{x+10}}
\\\\\\
\lim\limits_{x\to -10}~x-10\implies \lim\limits_{x\to -10}~-10-10\implies -20$

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3 years ago

What’s The Answer Of This? Please Answer ASAP

Radda [10]

Answer: 67 degrees

Step-by-step explanation:

4 0

2 years ago

For each student in a certain class, a teacher adjusted the student's test score using the formula y = 0.8x + 20, where x is the

alexandr402 [8]

Answer:

Option B) 16

Step-by-step explanation:

We are given the following in the question:

$y = 0.8x + 20$

where x is the student's original test score and y is the student's adjusted test score.

We have to find the standard deviation of the adjusted test scores of the students in the class, if the standard deviation of the original test scores of the students in the class was 20.

We know that:

Adding a constant to each value in a data set does not change the value of the standard deviation.
Multiplying each value in a data set by a constant also multiplies the standard deviation by that constant.

Thus, if we add 20 to each data set then, the standard deviation does not change.

But multiplying each score by 0.8, changes the standard deviation 0.8 times.

Thus, we can write:

$\text{Standard deviation of the adjusted test scores}\\ = \text{Standard deviation of the original test scores of the students}\times 0.8\\= 20\times 0.8\\= 16$

Thus, standard deviation of adjusted score is 16.

5 0

3 years ago