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2 years ago

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Can help me with this Please?

1 answer:

pentagon [3]2 years ago

7 0

Answer:

where's the question at ?

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find a positive angle less than one revolution around the unit circle that is co-terminal with the given angle -15pi/17

natta225 [31]

ANSWER
$=\frac{19}{17} \pi$

EXPLANATION

To find a positive angle that is coterminal with
$- \frac{15}{17} \pi$

We add multiples of 2π until we get a positive angle that is less than one revolution,

We add to obtain,

$- \frac{15}{17} \pi + 2\pi$

This simplifies to,

$= \frac{19}{17} \pi$

This is the first positive angle that is coterminal with
$- \frac{15}{17} \pi$

and is less than one revolution.

7 0

3 years ago

What is the rate in feet per second? 10 feet 16 seconds

Ierofanga [76]

Feet
_____
second

10 feet
________
16 second

equals

.625 feet per second

7 0

2 years ago

Write this ratio 1:3.5 in the form p:q where p and q are whole numbers

Orlov [11]

We have to express the ratio 1 : 3.5 in the form p:q where p and q are whole numbers.

Consider the ratio of 1 and 3.5,

1 : 3.5 = $\frac{1}{3.5}$

= $\frac{10}{35}$

Reducing the above fraction to its lowest form.

So, we get $\frac{10}{35}=\frac{2}{7}$

Therefore, the ratio 1 : 3.5 is expressed as $\frac{2}{7}$

where 2 and 7 are the whole numbers.

4 0

2 years ago

Sergey is solving 5x2 + 20% – 7 = 0. Which steps could he use to solve the quadratic equation by completing the

Mrac [35]

Answer:

$5(x^2+4x)=7$

$5(x^2+4x+4)=7+20$

$(x+2)=\pm\sqrt{\frac{27}{5}}$

Step-by-step explanation:

we have

$5x^2+20x-7=0$

step 1

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$5x^2+20x=7$

step 2

Factor 5 left side

$5(x^2+4x)=7$

step 3

Complete the square

$5(x^2+4x+2^2)=7+2^2(5)$

$5(x^2+4x+4)=7+20$

$5(x^2+4x+4)=27$

step 4

Rewrite as perfect squares

$5(x+2)^2=27$

step 5

$(x+2)^2=\frac{27}{5}$

$(x+2)=\pm\sqrt{\frac{27}{5}}$

$(x+2)=\pm\frac{3\sqrt{15}}{5}$

step 6

$x=-2\pm\frac{3\sqrt{15}}{5}$

6 0

3 years ago

Read 2 more answers

Help me plz ASAP

Hatshy [7]

The equation has one solution

4 0

3 years ago