When pigments are mixed together, more colors are being absorbed which results to few colors that will be reflected. Each pigment absorbs and reflects light which results to the "color" or hue that we see. When these pigments are to be mixed, then more wavelengths would be absorbed which results to lesser reflection.
Answer:
Explanation:
To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.
The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.
So, en the exposed example:
- J and K are autosomal genes
- J and K are separated by 60 M.U.
- 60 M.U. means that there is 60% of recombination.
Cross) J K / j k x j k / j k
Gametes) JK Parental jk, jk, jk, jk
jk Parental
Jk Recombinant
jK Recombinant
One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.
1 M.U. -------------- 1% recombination
60 M.U. ------------ 60% recombination
30% Jk + 30% jK
100 M.U. - 60 M.U. = 40 M.U.
40M.U.--------------40 % Parental (Not recombinant)
20% JK + 20% jk
Punnet Square) JK jk Jk jK
jk JK/jk jk/jk Jk/jk jK/jk
J K / j k = 20%
j k / j k = 20%
J k / j k = 30%
j K / j k = 30%
Weather changes every day, while climate changes annually or every 3 months
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Answer:
Q(0) = 0C, Q(1) = 264nC, Q(2) = 952C Q(3) = 2088nC, Q(4) = 3696C Q(5) = 5800nC
Explanation:
I = 4t³ + 200t² + 60t
But charge of an object =》 Q = IT
Charge of an object is the product of the current and the time in which the current passes through the membrane.
When t = 0
Q = 4(0)³ + 200(0)² + 60(0) = 0C
When t = 1
Q = 4(1)³ + 200(1)² + 60(1) = 264nC
When t = 2
Q = 4(2)³ + 200(2)² + 60(2) = 952nC
When t= 3
Q = 4(3)³ + 200(3)² + 60(3) = 2088nC
When t= 4
Q = 4(4)³ + 200(4)² + 60(4) = 3696nC
When t = 5
Q = 4(5)³ + 200(5)² + 60(5) = 5800nC
