How to solve for quadratic equations with inequalities?

1 answer:

3 0

First solve the quadratic as you would an equation, so you will get two real zeroes p and q so that (x-p)(x-q)=0 is another way of expressing the quadratic. All quadratics can be represented graphically by a parabola, which could be inverted. When the x² coefficient is negative it’s inverted. If the coefficient of x² isn’t 1 or -1 divide the whole quadratic by the coefficient so that it takes the form x²+ax+b, where a and b are real fractions. The curve between the zeroes will be totally below the x axis for an upright parabola, and totally above for an inverted parabola. This fact is used for inequalities. An inequality will be <, ≤, > or ≥. This makes it easy to solve the inequality. If the position of the curve between the zeroes is below the axis then outside this interval it will be above, and vice versa. So we’ve defined three zones. x

q, and p

You might be interested in

Sharon is jumping from an 18-foot diving board with an initial upward velocity of 4 ft/s. when sharon jumps, megan throws a beac

Alinara [238K]

It will take 1.08 seconds for the ball to reach Sharon after she jumps if the upward velocity of the ball is 16 ft/s from a height of 5 feet option third is correct.

<h3>What is the equation of motion?</h3>

It is defined as the equation by which we can find the motion of a physical particle with respect to time. It is the representation of physical entity movement in a mathematical function.

We have:

The height of the Sharon from the diving board = 18 feet

The initial upward velocity of the Sharon = 4 ft/s

The height of the Megan from the ground = 5 feet

The initial upward velocity of the beach ball = 16 ft/s

We know the equation of motion is given by:

$\rm h(t) = x + ut+\frac{1}{2} gt^2$

Put x = 18 feet and u = 4 ft/s in the above equation, we get:

$\rm h(t) = 18 + 4t+\frac{1}{2} \times9.8t^2$ ....(1) [g = 9.8 m/s²]

Put x = 5 feet and u = 16 ft/s in the equation of motion, we get:

$\rm h(t) = 5 + 16t+\frac{1}{2} \times9.8t^2$ ....(2)

Equate the equation (1) and equation (2), we get

$\rm 18 + 4t+\frac{1}{2} \times9.8t^2= 5 + 16t+\frac{1}{2} \times9.8t^2\\$

18 + 4t = 5 + 16t

12t = 13

t = 1.08 seconds

Thus, it will take 1.08 seconds for the ball to reach Sharon after she jumps if the upward velocity of the ball is 16 ft/s from a height of 5 feet.

Learn more about the equation of the motion here:

brainly.com/question/13514745

6 0

3 years ago

−3(2+4k)+7(2k−1) eqivalent expression

Alex17521 [72]

Answer:

$\large\boxed{-3(2+4k)+7(2k-1)=2k-13}$

Step-by-step explanation:

$-3(2+4k)+7(2k-1)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(-3)(2)+(-3)(4k)+(7)(2k)+(7)(-1)\\\\=-6-12k+14k-7\qquad\text{combine like terms}\\\\=(-12k+14k)+(-6-7)\\\\=2k-13$