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Novosadov [1.4K]
3 years ago
5

Help pls . .. a a z z z z . zz

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
6 0
I believe it’s Perpendicular
So sorry if it’s wrong
zloy xaker [14]3 years ago
4 0

Answer:

the lines are perpendicular

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Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if:a) a
lara31 [8.8K]

Answer:

A) 0.0009765625

B) 0.0060466176

C) 2.7756 x 10^(-17)

Step-by-step explanation:

A) This problem follows a binomial distribution. The number of successes among a fixed number of trials is; n = 10

If a 0 bit and 1 bit are equally likely, then the probability to select in 1 bit is; p = 1/2 = 0.5

Now the definition of binomial probability is given by;

P(K = x) = C(n, k)•p^(k)•(1 - p)^(n - k)

Now, we want the definition of this probability at k = 10.

Thus;

P(x = 10) = C(10,10)•0.5^(10)•(1 - 0.5)^(10 - 10)

P(x = 10) = 0.0009765625

B) here we are given that p = 0.6 while n remains 10 and k = 10

Thus;

P(x = 10) = C(10,10)•0.6^(10)•(1 - 0.6)^(10 - 10)

P(x=10) = 0.0060466176

C) we are given that;

P((x_i) = 1) = 1/(2^(i))

Where i = 1,2,3.....,n

Now, the probability for the different bits is independent, so we can use multiplication rule for independent events which gives;

P(x = 10) = P((x_1) = 1)•P((x_2) = 1)•P((x_3) = 1)••P((x_4) = 1)•P((x_5) = 1)•P((x_6) = 1)•P((x_7) = 1)•P((x_8) = 1)•P((x_9) = 1)•P((x_10) = 1)

This gives;

P(x = 10) = [1/(2^(1))]•[1/(2^(2))]•[1/(2^(3))]•[1/(2^(4))]....•[1/(2^(10))]

This gives;

P(x = 10) = [1/(2^(55))]

P(x = 10) = 2.7756 x 10^(-17)

3 0
3 years ago
Most ATM’s require a 4-digit code using the digits 0-9 how many 4-digit codes can you use
Zolol [24]

10000 digits can be used for 4 digit A.T.M code.

<u>Solution:</u>

Given that A.T.M required 4 digit codes using the digits 0 to 9.  

Need to determine how many four digit code can be used.

We are assuming that number starting with 0 are also valid ATM codes that means 0789 , 0089 , 0006 and 0000 are also valid A.T.M codes.

Now we have four places to be filled by 0 to 9 that is 10 numbers

Also need to keep in mind that repetition is allowed in this case means if 9 is selected at thousands place than also it is available for hundreds, ones or tens place .  

First digit can be selected in 10 ways that is from 0 to 9.

After selecting first digit, second digit can be selected in 10 ways that is 0 to 9 and same holds true for third and fourth digit.

So number of ways in which four digit number is created = 10 x 10 x 10 x 10 = 10000 ways

Hence 10000 digits can be used for 4 digit A.T.M code.

7 0
2 years ago
In rectangle PQRS, SQ = 78, PS = 30, and mPRS = 23°. Find SR.
kondor19780726 [428]
\cos (23)=\frac{sr}{78}\rightarrow78\cdot\cos (23)=SR=67.20

7 0
1 year ago
The difference of two numbers is 90 and their quotient is 10
bija089 [108]
To solve this, set up two equations using the information you're given. Let's call our two numbers a and b:
1) D<span>ifference of two numbers is 90
a - b (difference of two numbers) = 90

2) The quotient of these two numbers is 10
a/b (quotient of the two numbers) = 10


Now you can solve for the two numbers.
1) Solve the second equation for one of the variables. Let's solve for a:
a/b = 10
a = 10b

2) Plug a =10b into the first equation and solve for the value of b:
a - b = 90
10b - b = 90
9b = 90
b = 10

3) Using b = 10, plug it back into one of the equations to find the value of a. I'll plug it back into the first equation:
a - b = 90
a - 10 = 90
a = 100

-------

Answer: The numbers are 100 and 10</span>
3 0
3 years ago
Simplify by dividing (3/5) divided by -4/9
Anton [14]

\bf \cfrac{3}{5}\div \cfrac{-4}{9}\implies \cfrac{3}{5}\cdot \cfrac{9}{-4}\implies \cfrac{27}{-20}\implies -1\frac{7}{20}

8 0
3 years ago
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