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Vinil7 [7]
3 years ago
10

Javier bought 2 adult movie tickets and 4 children’s movie tickets and spent a total of $46. If adult tickets cost $2 more than

children’s tickets,how much does each type of ticket cost?
Mathematics
1 answer:
Sergio [31]3 years ago
6 0
The children's ticket would be $7 each and the adult ticket would be $9.
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Log(5) + log(3) rewrite the following in the form log(c).
Dennis_Churaev [7]
Log (5) + log (3) = log (15)
3 0
3 years ago
Read 2 more answers
Surface area of this right prism
Sphinxa [80]

\qquad\qquad\huge\underline{{\sf Answer}}

\textsf{Let's calculate the surface area of given right prism}

\textbf{Area of Triangles :}

  • \sf{\dfrac{1}{2}\cdot 16\cdot 12}

  • \sf{8×12}

  • \sf96 \:  \: cm {}^{2}

\textsf{Since there are two triangles, }

\textsf{Area of Triangles = 96 × 2 = 192 cm²}

\textbf{Now, calculate the Areas of rectangles :}

  • \textsf{Area - 1 = 12 × 10 = 120 cm²}

  • \textsf{Area - 2 = 16 × 10 = 160 cm²}

  • \textsf{Area - 3 = 20 × 10 = 200 cm²}

\textsf{Now add them all :}

  • \textsf{120 + 160 + 200 + 192}

  • \textsf{672 cm²}

7 0
2 years ago
Read 2 more answers
1.hi students I have a question for you
katen-ka-za [31]

Answer:

the answer of given question is $400.

6 0
2 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
Please help i have 2 questions thank you very much.
Rudik [331]
Hello!

Question 1
We first have to convert everything to yards since the concrete is charged by the cubic yards

15 feet = 5 yards
15 feet = 5 yards
3 inches = 0.08333

Multiply these to find the volume

5 * 5 * 0.08333 = 2.08325

Multiply this by the cost

2.08325 * 46 = 95.83

The answer is C) $95.83
------------------------------------------------------------------------------------------------------
Question 2

You have to find the volume of the first pyramid

The equation we use is V = \frac{lwh}{3}

V is volume
l is length
w is width
h is height

Put in the values we know

V =  \frac{16 * 16 * 28}{3}

Multiply

V =  \frac{7168}{3}

Divide

V = 2389.3333

Now we use this to find the side length of the second pyramid

2389.333 =  \frac{lw * 112}{3}

Multiply both sides by 3

<span>7167.999 = lw * 112
</span>
Divide both sides by 112

63.9999 = lw

Since it is a square pyramid we know that sides are equal

63.999 = l^2

Take the square root of both sides

8 = l

The answer is B) 8in

Hope this helps!
8 0
3 years ago
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