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2 years ago

10

Javier bought 2 adult movie tickets and 4 children’s movie tickets and spent a total of $46. If adult tickets cost $2 more than

children’s tickets,how much does each type of ticket cost?

1 answer:

Sergio [31]2 years ago

6 0

The children's ticket would be $7 each and the adult ticket would be $9.

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what is a correct first step in solving the inequality –4(3 – 5x)≥ –6x 9? –12 – 20x ≤ –6x 9 –12 – 20x ≥ –6x 9 –12 20x ≤ –6x 9 –1

suter [353]

we have

$-4(3-5x) \geq -6x+9$

Step 1

Applying the distributive property in the left side ( Multiply the factors on the left side)

$-4(3-5x) \geq -6x+9\\- 4*3+4*5x\geq -6x+9\\-12+20x\geq -6x+9$

therefore

<u>the answer is</u>

$-12+20x\geq -6x+9$

8 0

2 years ago

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Sergio is S years old. Which expression shows how old will he be 7 years from now?

aniked [119]

The answer is C.

If Sergio is 'S' years old, and you want to know how old he'll be in 7 years, add 7 years to his age.

So: s + 7

Hope this helps!

3 0

3 years ago

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Shonda goes to a restaurant with no more than $15 to spend. She buys a burger that costs

andrew11 [14]

Answer:

she has 4.5

and she should´ve got bacon egg and cheese than that burger

5 0

2 years ago

For a particular event, 669 tickets were sold for a total of $4293. If students paid $5 per ticket and nonstudents paid $8 p

solong [7]

Answer:

353 tickets.

Step-by-step explanation:

Let's say that there are s student tickets and n nonstudent tickets.

s + n = 669

5s + 8n = 4293

Multiply -5 by the entire first equation to get...

-5s - 5n = -3345

Combine the two equations.

5s - 5s + 8n - 5n = 4293 - 3345

3n = 948

n = 316

Now, put the number of nonstudent tickets sold back into the first equation.

s + 316 = 669

s = 353 tickets.

Hope this helps!

5 0

3 years ago

a silo is shaped like a cylinderwith a cone on top. the radii of the bases of the cylinder and cone are both equal to 8 feet. th

Ymorist [56]

Answer:

5430.85 square feet

Step-by-step explanation:

Height of the cylindrical part of the cilo = 25 feet

radius of the base cylindrical part of cilo = 8 feet

Now volume of cylindrical part of cilo = $\pi r^{2} h$

Volume of cylindrical part of cilo = $\pi(8^{2})25$ = $1600\pi square feet$

Now,

Height of the conical part of cilo = 6 feet

Radius of the conical part of cilo = 8 feet

Volume of the conical part of cilo = $\frac{1}{3}\pi (8^{2})6$ = $128\pi square feet$

Volume of the entire cilo = $1600\pi + 128\pi = 1728\pi$

since $\pi =\frac{22}{7} therefore,$

volume of entire cilo = $\frac{22}{7} (1728)$ = 5430.85

3 0

3 years ago