The zeros of given function
is – 5 and – 3
<u>Solution:</u>

We have to find the zeros of the function by rewriting the function in intercept form.
By using intercept form, we can put value of y as to obtain zeros of function
We know that, intercept form of above equation is 


Taking “x” as common from first two terms and “3” as common from last two terms
x (x + 5) + 3(x + 5) = 0
(x + 5)(x + 3) = 0
Equating to 0 we get,
x + 5 = 0 or x + 3 = 0
x = - 5 or – 3
Hence, the zeroes of the given function are – 5 and – 3
3x-9=6x-2x tyhjijhvssd hbjhbbb. Schhybhb. Schhjhh. Scvbbhh. Vbbjjn. Baby
3 triangles.
If you take 3 toothpicks you create the first triangle. You put the last toothpick down the middle, you get 2 more
Step-by-step explanation:
180= 90+30+20x 90+30=120 180-120= 60
20x=60 x=3
Answer:
let the past stay in the past
Step-by-step explanation: