Ask question

Ask question

All categories

3 years ago

7

A vase is in the shape of a cone that is 10 inches tall and with a diameter of 3 inches. What is the greatest amount of water th

e vse can hold?

1 answer:

pickupchik [31]3 years ago

3 0

It can hold about 23.56 cubic inches of water

You might be interested in

ABCD- parallelogram, If the perimeter of Triangle CPQ is 15cm, Find the perimeter of triangle BAQ. Find the perimeter of triangl

melamori03 [73]

Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

Given parallelogram ABCD:

AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

$\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x} \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm$

Perimeter of CPQ = CP + CQ + PQ

15 = 6 + 8/3 + PQ

PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

$\frac{AQ}{QP}=\frac{AB}{CP} \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19$

$\frac{BQ}{CQ}=\frac{AB}{CP} \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8$

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

PA = AQ + PQ = 19 + 6.33 = 25.33

PD = CD + DP = 18 + 6 = 24

Perimeter of PDA = PA + PD + AD = 24 + 25.33 + 8 = 57.33 cm

7 0

3 years ago

8. Given: PQR and TSR are right triangles,

rewona [7]

Answer:

The answer is below

Step-by-step explanation:

A triangle is a polygon with three sides and three angles. Types of triangles are scalene, right angled, isosceles, equilateral.

A right angled triangle is a triangle with one angle equals to 90°.

Statement Reason

∠PQR = ∠RST Given. ∠PQR = ∠RST = 90° (definition for right

angle triangle.

PQ = ST Given

PR ≅ RT Since R is the midpoint of PT, hence PR = RT

ΔPQR ≅ ΔTSR Side-angle-side triangle congruence theorem.

the Side-angle-side triangle congruence theorem

states that if two sides and an included angle of

one triangle is equal to two sides and an included

angle of another triangle, then the two triangles

are congruent. PQ=ST, PR = RT and ∠PQR = ∠TSR

3 0

2 years ago

A brother is 3 years older than his sister. Five years ago, the ratio of their ages was 4 : 3. Find the boy age.

Wewaii [24]

17 years old
12:9
12 + 5 is 17

5 0

2 years ago

Which statement BEST compares the growth of the two functions as x approaches oo?

Karo-lina-s [1.5K]

Answer:

b girl main daal atom answer

Step-by-step explanation:

kas goal feel keep PCL pal PCL

6 0

3 years ago

This problem has been solved!See the answerA municipal bond service has three rating categories (A, B, and C). Suppose that in t

mariarad [96]

Answer:

a. $\frac{35}{51}$

b. $\frac{51}{100}$

c. $\frac{1}{5}$

Step-by-step explanation:

Suppose cities represented by C', suburbs represented by S and rural represented by R,

Let x be the total number of bonds issued throughout the US,

According to the question,

n(A) = 70% of x = 0.7x,

n(B) = 10% of x = 0.1x,

n(C) = 20% of x = 0.2x,

n(A∩C') = 50% of n(A) = 0.5 × 0.7x = 0.35x,

n(A∩S) = 20% of n(A) = 0.2 × 0.7x = 0.14x,

n(A∩R) = 30% of n(A) = 0.3 × 0.7x = 0.21x,

n(B∩C') = 40% of n(B) = 0.4 × 0.1x = 0.04x,

n(B∩S) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(B∩R) = 30% of n(B) = 0.3 × 0.1x = 0.03x,

n(C∩C') = 60% of n(C) = 0.6 × 0.2x = 0.12x,

n(C∩S) = 15% of n(C) = 0.15 × 0.2x = 0.03x,

n(C∩R) = 25% of n(C) = 0.25 × 0.2x = 0.05x,

n(C') = n(A∩C') + n(B∩C') + n(C∩C') = 0.35x + 0.04x + 0.12x = 0.51x

n(S) = n(A∩S) + n(B∩S) + n(C∩S) = 0.14x + 0.03x + 0.03x = 0.20x

a. The probability that it will receive an A rating, if a new municipal bond is to be issued by a city,

$P(\frac{A}{C'})=\frac{P(A\cap C')}{P(C')}=\frac{0.35x/x}{0.51x/x}=\frac{0.35}{0.51}=\frac{35}{51}$

b. The proportion of municipal bonds are issued by cities = $\frac{n(C')}{x}$

$=\frac{0.51x}{x}$

$=\frac{51}{100}$

c. The proportion of municipal bonds are issued by suburbs = $\frac{n(S)}{x}$

$=\frac{0.20x}{x}$

$=\frac{20}{100}$

$=\frac{1}{5}$

3 0

3 years ago