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jek_recluse [69]
3 years ago
7

in triangle abc, the size of angle b is 5 times the size of angle a and the size of angle c is 13° less than 4 times the size of

angle a. find the size of the angles
Mathematics
1 answer:
olasank [31]3 years ago
8 0
Sum of angles of a triangle = 180 
a+b+c=180
a + (5a) + (4a-13) = 180
Simplify and solve for a:
10a-13=180
10a=193
a=19.3
b=5*19.3=96.5
c=4*19.3-13=77.2-13=64.2
Check: a+b+c=19.3+96.5+64.2=180 ok.
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frutty [35]

Option A:

The equation for the trend line is y = 82x + 998.

Solution:

The points on the line are (2, 1162) and (11, 1900).

Here, x_1=2, y_1=1162, x_2 = 11, y_2=1900

Slope of the line:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

$m=\frac{1900-1162}{11-2}

$m=\frac{738}{9}

m = 82

Point-slope formula:

y-y_{1}=m\left(x-x_{1}\right)

y-1162=82\left(x-2\right)

y-1162=82x-164

Add 1162 on both sides of the equation.

y=82x+998

The equation for the trend line is y = 82x + 998.

Hence Option A is the correct answer.

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3 years ago
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Answer:

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Step-by-step explanation:

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The volume of a cylinder is 176 π cm and its height is 11 π cm.
Liula [17]

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
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Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant, 
USPshnik [31]

By definition of tangent,

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

Recall the double angle identities:

sin(2<em>θ</em>) = 2 sin(<em>θ</em>) cos(<em>θ</em>)

cos(2<em>θ</em>) = cos²(<em>θ</em>) - sin²(<em>θ</em>) = 2 cos²(<em>θ</em>) - 1

where the latter equality follows from the Pythagorean identity, cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1. From this identity we can solve for the unknown value of sin(<em>θ</em>):

sin(<em>θ</em>) = ± √(1 - cos²(<em>θ</em>))

and the sign of sin(<em>θ</em>) is determined by the quadrant in which the angle terminates.

<em />

We're given that <em>θ</em> belongs to the third quadrant, for which both sin(<em>θ</em>) and cos(<em>θ</em>) are negative. So if cos(<em>θ</em>) = -4/5, we get

sin(<em>θ</em>) = - √(1 - (-4/5)²) = -3/5

Then

tan(2<em>θ</em>) = sin(2<em>θ</em>) / cos(2<em>θ</em>)

tan(2<em>θ</em>) = (2 sin(<em>θ</em>) cos(<em>θ</em>)) / (2 cos²(<em>θ</em>) - 1)

tan(2<em>θ</em>) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2<em>θ</em>) = 24/7

4 0
3 years ago
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