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Anvisha [2.4K]
2 years ago
13

Consider a sample with data values of 26, 27, 20, 15, 30, 34, 28, and 20. Compute the range, interquartile range, variance, and

standard deviation (to a maximum of 2 decimals, if decimals are necessary).
Mathematics
1 answer:
marta [7]2 years ago
8 0

Answer:

r=19

IQR=9

SD=5.81

Step-by-step explanation:

Given the following data set:

26, 27, 20, 15, 30, 34, 28,20

To find the range of a data set we have to find the largest and the smallest number of the set and then subtract them.

26, 27, 20, 15, 30, 34, 28,20

34-15=19

r=19

To find the interquartile range we have to subtract the third quartile by the first quartile.

26, 27, 20, 15, 30, 34, 28,20

IQR=Q3-Q1

Q1=20

Q3=29

IQR=29-20=9

IQR=9

To find the standard deviation of a data set we have to use the formula to calculate standard deviation with the given values.

SD=\frac{(26-25)^2+...+(20-25)^2}{8}

SD=\frac{270}{8} =\sqrt{33.75} =5.8094750193111

5.8094750193111

9>5

SD=5.81

Hope this helps.

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Answer with Step-by-step explanation:

Let a mass weighing 16 pounds stretches a spring \frac{8}{3} feet.

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Mass=m=\frac{16}{32}

g=32 ft/s^2

Mass,m=\frac{1}{2} Slug

By hook's law

w=kx

16=\frac{8}{3} k

k=\frac{16\times 3}{8}=6 lb/ft

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A damping force is numerically equal to 1/2 the instantaneous velocity

\beta=\frac{1}{2}

Equation of motion :

m\frac{d^2x}{dt^2}=-kx-\beta \frac{dx}{dt}+f(t)

Using this equation

\frac{1}{2}\frac{d^2x}{dt^2}=-6x-\frac{1}{2}\frac{dx}{dt}+10cos(3t)

\frac{1}{2}\frac{d^2x}{dt^2}+\frac{1}{2}\frac{dx}{dt}+6x=10cos(3t)

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m=\frac{-1\pm\sqrt{1-4(1)(12)}}{2}

m=\frac{-1\pmi\sqrt{47}}{2}

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Complementary function

e^{\frac{-t}{2}}(c_1cos\frac{\sqrt{47}}{2}+c_2sin\frac{\sqrt{47}}{2})

To find the particular solution using undetermined coefficient method

x_p(t)=Acos(3t)+Bsin(3t)

x'_p(t)=-3Asin(3t)+3Bcos(3t)

x''_p(t)=-9Acos(3t)-9sin(3t)

This solution satisfied the equation therefore, substitute the values in the differential equation

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Now, the general solution

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