Answer:
(2, -4)
Step-by-step explanation:
1/2 x + 3/4 y = -2
2/3 x + 5/6 y = -2
4 (1/2 x + 3/4 y = -2 ) = -2(2x + 3y = -8) Multiply by -2 to eliminate the x's
6 (2/3 x + 5/6 y = -2) = (4x + 5y = -12)
<u> -4x - 6y = 16 </u> combine with the 2nd equation
-1y = 4
y = -4
plug -4 in for y to find x in either equation
1/2x + 3/4 (-4) =-2
1/2x - 3 = -2
1/2x = 1
x = 2
(2, -4)
Answer: x=68, y=37
Step-by-step explanation:
The equation for the sum of two numbers is 105 would be x+y=105. You can say the larger number would be x and the smaller would be y. So, x=2y-6. then you plug that into the x in the first equation.
2y-6+y=105
3y-6=105
3y=111
y=37
Then you would plug in the y to one of the equations. I will do the second one but you can do either one.
x=2y-6
x=2*37-6
x=74-6
x=68
Answer:
So i found the teacher notes after hours of looking here are the exact answers so i would recommend changing the wording.
Part A: Ordered pairs in the form (mb, kmh): (1,000, 100) and (960,180) Let X be the barometric pressure and Y be the wind speed.
Slope= (180-100)
---------------- = -2
(960-1000)
Formula: y=-2(x-1000)+100
Part B: y=-2(980-1000)+100=140
140 kmh is reasonable. Because 980 mb is halfway between 960 mb and 1000 mb, we should expect a wind speed halfway between 180 kmh and 100 kmh.
Part C: The wind speed intercept is (0,2100) [or (2100,0) if written that way.] This means that when brometric pressure is 0 mb, then the wind speed would be 2100 kmh. However in the context of real weather, this is an impossible situation.
Part D: The slope means that every decrease of 2 kmh in wind speed corresponds to a 1 mb increase in barometric pressure.
hoped this helped :)
Answer:
The area of the triangle is 351cm^2.
Step-by-step explanation:
To find the area of a triangle, the formula is (1/2) x base x height. In this case, the height would be a line that cuts straight through the center of the triangle. However, this height is not given to us. We can still find it through Pythagoras' Theorem though.
Let A be the tip of the triangle, and B and C be the points on either side of the triangle. Assuming an imaginary line that cuts the triangle in a symmetrical half, let T be the point at the end of the line, directly below point A.
Using Pythagoras' Theorem,
AB^2 = AT^2 + TB^2
AT^2 = AB^2 - TB^2
AT^2 = 30^2 - (26/2)^2
AT^2 = 30^2 - 13^2
AT =
![\sqrt{ {30}^{2} - {13}^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%20%7B30%7D%5E%7B2%7D%20%20-%20%20%7B13%7D%5E%7B2%7D%20%7D%20)
AT = 27.0370116692
So the length of AT is our height. We can now find the area of the triangle.
Area of triangle = (1/2) x 26cm x AT
Area of triangle = 351.4811516996
Area of triangle = 351cm^2 (To 3s.f.)
I don’t know the answer but I hope someone else doesnt