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dezoksy [38]
3 years ago
7

Please help, I've been working on this for 30 min now...

Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

Step 1: Y is equal to \frac{3}{4}x + 2 so where ever you see a y in the equation 3x - 4y = -5 replace it with \frac{3}{4}x + 2

3x - 4(\frac{3}{4}x + 2) = -5

Now all your variables are x and you can solve for x

Step 2: Distribute for to the numbers in the parentheses

3x - 3x - 8 = -5

Step 3: Combine like terms

0x - 8 = -5

0x = 3

Step 4: Isolate x

0x/0 = 3/0

3/0 is undefined

^^^ This means that there is no answer

If you look at the graph below you can see that these lines are parallel and therefore have no intersection point

Hope this helped!

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I’ve been on this one for an hour now, can someone help me lol
kirill115 [55]

Answer:

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Step-by-step explanation:

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2 years ago
A tank contains 9,000 L of brine with 18 kg of dissolved salt. Pure water enters the tank at a rate of 90 L/min. The solution is
aev [14]

Let <em>x(t)</em> denote the amount of salt (in kg) in the tank at time <em>t</em>. The tank starts with 18 kg of salt, so <em>x</em> (0) = 18.

The solution is drained from the tank at a rate of 90 L/min, so that the amount of salt in the tank changes according to the differential equation

d<em>x(t)</em>/d<em>t</em> = - (<em>x(t)</em> kg)/(9000 L) × (90 L/min) = -1/100 <em>x(t)</em> kg/min

or, more succintly,

<em>x'</em> = -1/100 <em>x</em>

This equation is separable as

d<em>x</em>/<em>x</em> = -1/100 d<em>t</em>

Integrating both sides gives

∫ d<em>x</em>/<em>x</em> = -1/100 ∫ d<em>t</em>

ln|<em>x</em>| = -1/100 <em>t</em> + <em>C</em>

<em>x</em> = exp(-1/100 <em>t</em> + <em>C </em>)

<em>x</em> = <em>C</em> exp(-<em>t</em>/100)

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18 = <em>C</em> exp(0)   ==>   <em>C</em> = 18

so that

<em>x(t)</em> = 18 exp(-<em>t</em>/100)

(b) After 20 minutes, we have

<em>x</em> (20) = 18 exp(-20/100) = 18 exp(-1/5) ≈ 14.74

so the tank contains approximately 14.74 kg of salt after this time.

7 0
3 years ago
How do I find the answer​
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5 0
3 years ago
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