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dezoksy [38]
3 years ago
7

Please help, I've been working on this for 30 min now...

Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

Step 1: Y is equal to \frac{3}{4}x + 2 so where ever you see a y in the equation 3x - 4y = -5 replace it with \frac{3}{4}x + 2

3x - 4(\frac{3}{4}x + 2) = -5

Now all your variables are x and you can solve for x

Step 2: Distribute for to the numbers in the parentheses

3x - 3x - 8 = -5

Step 3: Combine like terms

0x - 8 = -5

0x = 3

Step 4: Isolate x

0x/0 = 3/0

3/0 is undefined

^^^ This means that there is no answer

If you look at the graph below you can see that these lines are parallel and therefore have no intersection point

Hope this helped!

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3 years ago
The sum of 2 fractions is 5/6. Their difference is 1/2. Their least common denominator is 6. The denominator of one is twice the
valentinak56 [21]

Answer:

Step-by-step explanation:

Alright, lets get started.

Suppose the first fraction is : \frac{a}{b}

Suppose the second fraction is : \frac{c}{d}

The sum of both fraction is given as : \frac{5}{6}

\frac{a}{b}+\frac{c}{d}=\frac{5}{6}    .......................equation (1)

The difference of both fraction is given as : \frac{1}{2}

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Adding equation (1) and equation (2)

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making common denominator

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Hence,

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Plugging the value of \frac{a}{b} in equation (1)

\frac{2}{3}+\frac{c}{d}=\frac{5}{6}

Subtracting \frac{2}{3} in both sides

\frac{c}{d}=\frac{5}{6}-\frac{2}{3}

\frac{c}{d}=\frac{1}{6}

Hence both fractions are \frac{2}{3} \ and \  \frac{1}{6}     ...................Answer

Hope it will help :)

7 0
2 years ago
Please show ALL YOUR WORK and how u came to the conclusion.
hichkok12 [17]

Answer:

A

Step-by-step explanation:

clearly, the equation has to allow t=0, and for that point we need to get 100% (of carbon-14) as result.

and so we also see, that the function calculates the % of the remaining carbon-14.

so, we need the desired outcome 60(%),

because 60 = 100 - 40.

and again, we need a function that shows t=0.

the only answer option fulfilling both criteria is A.

B divides in the exponent by t, so t=0 is not in the domain of the function.

and C and D aim for the wrong remaining percentage.

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