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ella [17]
4 years ago
5

Which sample of matter represents a mixture?

Chemistry
2 answers:
valina [46]4 years ago
5 0
A mixture is a new substance that you get when you mix two or more different substances together and blend them so you either create a homogeneous mixture, or a heterogeneous one. In you case (assuming that your choices are aqueous ammonia, liquid mercury, gaseous ethane, solid iodine), the correct answer is aqueous ammonia, given that it is a mixture of ammonia and water, whereas the other options are not mixtures because they only consist of one element.
ollegr [7]4 years ago
4 0

A mixture is a new substance that you get when you mix two or more different substances together and blend them so you either create a homogeneous mixture or a heterogeneous one. In your case (assuming that your choices are aqueous ammonia, liquid mercury, gaseous ethane, solid iodine), the correct answer is aqueous ammonia, given that it is a mixture of ammonia and water, whereas the other options are not mixtures because they only consist of one element.

Explanation:


In chemistry, a combination forms once 2 or additional substances are combined such every substance retains its own chemical identity. Chemical bonds between the elements area unit neither broken nor fashioned. Note that albeit the chemical properties of the elements haven't modified, a combination could exhibit new physical properties, like boiling purpose and freezing point. For instance, combining along water and alcohol produces a combination that features a higher boiling purpose and lower freezing point than alcohol.

You might be interested in
What quantity of copper is deposited by the same quantity of electricity that deposited 9g of aluminum
klio [65]

Answer:

Mass of copper deposited = 31.75 g

Explanation:

According to Faraday's second law of electrolysis, when the same quantity of electricity is passed through different electrolytes, the relative number of moles of the elements deposited are inversely proportional to the charges on the ions of the elements.

From this law, it can be seen that the higher the charge, the lower the number of moles of a given element deposited.

Number of moles of aluminium in 9 g of aluminium = mass / molar mass

Molar mass of aluminium = 27 g

Number of moles of aluminium = 9/27 = 1/3 moles

Charge on aluminium ion = +3

3 moles of electrons will discharge 1 mole of aluminium,

1 mole of electrons will discharge 1/3 moles of aluminium

Number of moles of electrons involved = 1 mole of electrons

Charge on copper ion = +2

1 mole of electrons will discharge 1/2 moles of copper.

Mass of 1/2 moles of copper = number of moles × molar mass of copper

Molar mass of copper = 63.5 g

Mass of copper deposited = 1/2 × 63.5 = 31.75 g

3 0
3 years ago
Predict the Products and then Balance: H2CO3 =
Tom [10]

Answer:

(A) H2CO3 = H20 + CO2

Explanation:

Carbonic acid is formed from carbon dioxide and water so its equation will be

H2CO3 → H2O + CO2

The equation is balanced as same no of atoms of each specie is present both sides

6 0
3 years ago
What are the following products for this equation FeN + Ca
irina1246 [14]
The answer would be Ca + FeN = Ca3N2 + 2Fe
6 0
3 years ago
The ph of a 0.55 m aqueous solution of hypobromous acid, hbro, at 25.0 °c is 4.48. what is the value of ka for hbro?
Alex Ar [27]

____________________________________________________

Answer:

Your answer would be a). 2.0 × 10-9

____________________________________________________

Work:

In your question the "ph" of a 0.55 m aqueous solution of hypobromous acid temperature is at 25 degrees C, and it's "ph" is 4.48.

You would use the ph (4.48) to find the ka for "hbro"

[H+]

=

10^-4.48

=

3.31 x 10^-5 M

=

[BrO-]

or: [H+] = 10^-4.48 = 3.31 x 10^-5 M = [BrO-]

Then you would find ka:

(3.31 x 10^-5)^2/0.55 =2 x 10^-9

____________________________________________________

<em>-Julie</em>

6 0
3 years ago
Question 2
Naddika [18.5K]

Answer:

38.4 atm

Explanation:

Data obtained from the question include:

V1 (initial volume) = 3200 L

P1 (initial pressure) = 3.00 atm

V2 (final volume) = 250.0 L

P2 (final pressure) = ?

Using Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:

P1V1 = P2V2

3 x 3200 = P2 x 250

Divide both side by 250

P2 = 3 x 3200/250

P2 = 38.4 atm

Therefore, the pressure of the gas if ethylene is supplied by a 250.0 L tank is 38.4 atm

5 0
4 years ago
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