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3 years ago

Find the mole fraction of benzene and toluene in solution containing

Chemistry

1 answer:

Mrac [35]3 years ago

5 0

Answer:

The mole fraction of benzene and toluene in solution containing mole fraction of benzene and toluene in solution containing is 45.9%

Explanation:

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what element has the electron configuration of 1s22s22p63s23p64s23d104p65s24d105p66s24f 145d106p67s25f 146d8

LekaFEV [45]

It is the darmstadtium element that has the electron configuration above and the atomic number of 110

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3 years ago

Which of these four elements is the most reactive metal?

Gala2k [10]

Answer:

Sodium is most reactive metal among these. Sodium is present in group one. It is alkali metal.

Explanation:

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3 years ago

A 150.0 mL sample of an aqueous solution at 25°C contains 15.2 mg of an unknown nonelectrolyte compound. If the solution has an

inysia [295]

Answer: The molar mass of the unknown compound is 223.2 g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

where,

$\pi$ = osmotic pressure of the solution = 8.44 torr

i = Van't hoff factor = 1 (for non-electrolytes)

M = molarity of solute = ?

R = Gas constant = $62.3637\text{ L torr }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$8.44torr=1\times M\times 62.3637\text{ L. torr }mol^{-1}K^{-1}\times 298K\\\\M=\frac{8.44}{1\times 62.3637\times 298}=4.54\times 10^{-4}M$

To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

We are given:

Molarity of solution = $4.54\times 10^{-4}M$

Given mass of unknown compound = 15.2 mg = 0.0152 g (Conversion factor: 1 g = 1000 mg)

Volume of solution = 150.0 mL

Putting values in above equation, we get:

$4.54\times 10^{-4}M=\frac{0.0152\times 1000}{\text{Molar mass of unknown compound}\times 150.0}\\\\\text{Molar mass of unknown compound}=\frac{0.0152\times 1000}{150.0\times 4.54\times 10^{-4}}=223.2g/mol$

Hence, the molar mass of the unknown compound is 223.2 g/mol

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3 years ago

Instructions:Select the correct answer. If 155 grams of potassium (K) reacts with 122 grams of potassium nitrate (KNO3), what is

Ivenika [448]

31310 / 390 => 80.28 g of KNO3 ( K is limiting reagent )

6 0

3 years ago

Read 2 more answers

An aqueous solution that is 20.0 percent sulfuric acid (h2so4) by mass has a density of 1.105 g/ml. determine the molarity of th

GuDViN [60]

The definition of molarity is:

Molarity = moles of solute / total volume of solution in Liters

In this case, our solute is Sulfuric Acid. To solve this problem, let us assume a basis for calculation.

Let us say that,

Total mass of solution = 100 g

Therefore mass of H2SO4 = 20 g

The molar mass of H2SO4 = 98.079 g / mol

Calculating for number of moles of H2SO4:

number of moles = 20 g / (98.079 g / mol)

number of moles = 0.204 mol

Calculating for the volume of solution using the density:

total volume of solution = 100 g / (1.105 g / mL)

total volume of solution = 90.50 mL = 0.0905 L

Therefore the molarity is:

Molarity = 0.204 mol / 0.0905 L

Molarity = 2.2542 mol / L

Molarity = 2.25 M

3 0

3 years ago

Find the mole fraction of benzene and toluene in solution containing​

Find the mole fraction of benzene and toluene in solution containing