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DIA [1.3K]
3 years ago
14

Write an electron configuration for an atom of aluminum-27 in an excited state

Chemistry
2 answers:
andrew11 [14]3 years ago
8 0
Ground state of Al  is 1s²2s²2p⁶3s²3p¹.
Exited state of Al is 1s²2s²2p⁶3s¹3p².
Alexus [3.1K]3 years ago
8 0

Answer: 1s^22s^22p^63s^13p^2.

Explanation:

Electronic configuration is defined as the distribution of electrons in the energy levels around an atomic nucleus.

Atomic number helps in determining the electronic distribution  of an atom. We write electronic configuration according to Aufbau's principle in which shells are arranged in increasing energy levels.

Aluminium (Al) is a p block element and its atomic number is 13.

Electronic configuration of aluminium is 1s^22s^22p^63s^23p^1.

Excite state is achieved when the electron moves to a higher energy level.The 3s electron moves to 3p orbital so that it can form three bonds.

Thus Electronic configuration of aluminium in an excited state is 1s^22s^22p^63s^13p^2.

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The %  composition   when 10g of magnesium combine   with  4g of   nitrogen  is  71.43%   magnesium   and  28.57 %  nitrogen

               calculation

%
  composition  =  mass  of an element  / total mass  x100
mass  of magnesium = 10 g
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calculate  the  total  mass  used

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%   composition for  magnesium  is therefore  =  10/14  x100 = 71.43 %

%  
composition  for  nitrogen  is therefore = 4 /14  x100  =   28.57 %
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