Ask question

Ask question

All categories

3 years ago

10

Mr. Cohen drives 84 2/10 miles on Tuesday, 84 6/10 mils on Wednesday, and 85 miles on Thursday. What is the rule fore the distan

ce Mr. Cohen drove? If this pattern continued what would be the next number?
please help me i have no parent home to help

1 answer:

GenaCL600 [577]3 years ago

8 0

+.4 miles everyday and the next number would be 95.4

You might be interested in

HELP ME PLEASE CANT UNDERSTAND!!!!

pshichka [43]

Answer:

i can,t see

Step-by-step explanation:

7 0

3 years ago

Identify the expression equivalent to 4(x + x + 7) − 2x + 8 − 4 by substituting x = 1 and x = 2. 6x + 11 3(x + 7) 2(3x + 16) 3x

Ratling [72]

The first one is 34, 4(9)-2+4
the second one is 12+113(9)

3 0

4 years ago

Read 2 more answers

Explain why the simultaneous equations y = -2/3x + 4/3 and 12x + 18y = 24 have an infinite number of solutions. What can you ded

denpristay [2]

Answer:

It's the same equation

Step-by-step explanation:

12x+18y=24

y=(-12x+24)/18

y=-2/3x+4/3

The intersect is the solution, so there are infinitely many solutions

4 0

3 years ago

The formula for the volume V of a cylinder is LaTeX: V=\pi r^2hV = π r 2 h, where r is the radius of the base anThe formula for

Alekssandra [29.7K]

Answer:

$h = \frac{V}{\pi r^2}$

$h = 4 cm$

Step-by-step explanation:

Volume of cylinder is given as $V = \pi r^2 h$

V is the volume the cylinder, r is its radius at the base, while is its height.

To select the formula for h (height) let's make h the subject of the formula as follows:

$V = \pi r^2 h$

$\frac{V}{\pi r^2} = \frac{\pi r^2 h}{\pi r^2}$ (dividing both sides of the equation by $\pi r^2$ )

$\frac{V}{\pi r^2} = h$

$h = \frac{V}{\pi r^2}$

Use the formula above to find the height of the given cylinder where Volume (V) = 36π cm³, and base radius (r) = 3 cm:

$h = \frac{36 \pi}{\pi 3^2}$ (substitution)

$h = \frac{36 \pi}{\pi * 9}$

$h = \frac{36 \pi}{9 \pi}$

$h = \frac{36 \pi}{\pi * 9}$

$h = \frac{36}{9}$ ( $\pi$ cancels $\pi$ )

$h = 4 cm$

8 0

3 years ago

Can someone please help me with one or both of these problems, I'm so confused but the assignment is due soon!!

Firlakuza [10]

Answer:

First question: 1270

Second question: 4080

Step-by-step explanation:

Here is the Sum formula:

$S_{n}=\frac{n}{2}(a_{1}+a_{n})$

where n represents the number of terms, and

$a_{1}$ is the first term, and $a_{n}$ is the last term.

Let's look at the first question:

k is the first number of the sequence, 5, and 20 is the last number of the sequence.

You can find the first term ( $a_{1}$ ) by substituting k in the formula for 5.

3(5)+26=15+26=41

You can find the last term ( $a_{n}$ ) by substituting k for 20 into the formula.

3(20)+26=60+26=86

now, knowing there are 20 terms in total, $a_{1} =41$ , and $a_{n} =86$ , we can put it into the Sum formula.

$S_{20}= \frac{20}{2} (41+86)$

$S_{20}= \frac{20}{2} (127)$

$S_{20}= 10 (127)$

$S_{20}= 1270$

Answer to the first question: 1270

Next question:

Even though the given formula uses n as the variable, this problem works the same way as the previous one.

Substitute n in the formula for k, which is 5 to find the first term: 14(5)+29=99

Substitute 20 for n to find the second term: 14(20)+29=309

Now assemble the Sum formula:

$S_{20}= \frac{20}{2} (99+309)$

$S_{20}= \frac{20}{2} (408)$

$S_{20}= 10(408)$

$S_{20}=4080$

Answer to the second question: 4080

5 0

3 years ago