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musickatia [10]
3 years ago
11

On the map of an amusement park on a coordinate grid, the skating rink is at (−1.5, −1).

Mathematics
2 answers:
inessss [21]3 years ago
6 0
The first option is correct.

Moving 1.5 units to the left (or -1.5 units to the right).
Moving 1 unit down (or -1 unit up).

Therefore you get the result of (-1.5, 1) as is the location of the rink.
Lana71 [14]3 years ago
3 0

Answer:

The correct option is 1.

Step-by-step explanation:

It is given that the skating rink is at (−1.5, −1).

Here, x-coordinate is -1.5 and y-coordinate is -1.

In a point P(a,b),

If a>0, then the point P is a units right from the origin and if a<0, then the point P is a units left from the origin.

If b>0, then the point P is b units up from the origin and if b<0, then the point P is b units down from the origin.

It the given point (-1.5, -1), a=-1.5 and b=-1 both are negative.

From the origin, move 1.5 units to the left along the x-axis and 1 unit vertically down, and place the point.

Therefore the correct option is 1.

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3 years ago
Simplify using the distributive property, Show all work (-2x - 9)(-4).
fgiga [73]
-2x(-4)=8x
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8x+36 is the answer
6 0
3 years ago
(3/5x + 4) + (1/5x -1)
kiruha [24]

Answer:

4/5x+3

Step-by-step explanation:

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3 0
3 years ago
For an employee training, the employee to instructor ratio is 24 to 2. If there are 26 instructors for the training, how many em
denpristay [2]

Answer:

312 employees participated in the training

Step-by-step explanation:

Given;

employee to instructor ratio is 24 to 2

there are 26 instructors for the training

let the total number of instructors be I = 26

let the total number of employees be e = ?

employee to instructor ratio is 24 to 2, e : I = 24 : 2

e : I = 24 : 2  = e : 26

\frac{24}{2} = \frac{e}{26} \\\\e = 12 *26\\\\e = 312

Therefore, the total number of employees who participated in the training is 312

8 0
2 years ago
PLEASE ANSWER i WILL PUT MOST BRAINLIEST!
galina1969 [7]

Answer:

The correct option is;

c. Because the p-value of 0.1609 is greater than the significance level of 0.05, we fail to reject the null hypothesis. We conclude the data provide convincing evidence that the mean amount of juice in all the bottles filled that day does not differ from the target value of 275 milliliters.

Step-by-step explanation:

Here we have the values

μ = 275 mL

275.4

276.8

273.9

275

275.8

275.9

276.1

Sum = 1928.9

Mean (Average), = 275.5571429

Standard deviation, s = 0.921696159

We put the null hypothesis as H₀: μ₁ = μ₂

Therefore, the alternative becomes Hₐ: μ₁ ≠ μ₂

The t-test formula is as follows;

t=\frac{\bar{x}-\mu }{\frac{s}{\sqrt{n}}}

Plugging in the values, we have,

Test statistic = 1.599292

t_{\alpha /2} at 7 - 1 degrees of freedom and α = 0.05 = ±2.446912

Our p-value from the the test statistic = 0.1608723≈ 0.1609

Therefore since the p-value = 0.1609 > α = 0.05, we fail to reject our null hypothesis, hence the evidence suggests that the mean does not differ from 275 mL.

4 0
3 years ago
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